Answer:
Both of these values don't have asymptotes.
The experimental probability of rolling a 6 is 9/60 which can be determined by dividing the frequency of the observation 6 with the total frequency of the experiment.
<u>Step-by-step explanation:</u>
Experimental probability is different from theoretical probability because the former is obtained by experimentation while the latter is what we expect theoretically.When we take a number of observations, the experimental probability and theoretical probability need not be the same.
In this question we have to determine the experimental probability of 6. It can be determined by dividing the frequency of the observation 6 by the total frequency of the experiment.
frequency of 6=9
total frequency=frequency of 1+frequency of 2+frequency of 3+frequency of 4+frequency of 5+frequency of 6
=13+11+9+8+10+9
=60
P(6)=frequency of 6/total frequency
=9/60
Answer:
I would say try D and then try A
Step-by-step explanation:
Answer:
C. (-3,11)
Step-by-step explanation:
Tp is (-3,6) implies the quadratic could have been
f(x) = (x+3)²+6
(2/3)f(x) = (2/3)[(x+3)²+6]
= (2/3)(x+3)²+4
(2/3)f(x)+3 = (2/3)(x+3)²+4+3
= (2/3)(x+3)²+7
Tp at (-3,7)
Alternately,
No change in domain so x remains-3
(2/3)f(x) changes y from 6 to 4 (6×2/3)
+3 increases the y by 3
i.e 4+3 = 7
So, (-3,7)
Answer:
The value of x is
.
Step-by-step explanation:
Given expression is:

We have to solve this for x.
First we will multiply both sides of the equation by 3

2(x-2) = 12x
2x-4=12x
Now we will be subtracting 2x from both sides of the equation
2x-2x-4=12x-2x
-4=10x
10x=-4
Dividing both sides by 10

Hence,
The value of x is
.