4(x-2)=4x-8 is this equation always true
2 answers:
Distribute 4 over the parentheses:-
4(x - 2) = 4x - 8 which is identical to the right side.
Yes - this is always true for any values of x, and its called an identity.
Yes, 4(x-2) is 4 times x-2 which using the distributive property gives you 4x-8 because 4 times x is 4x and 4 times -2 is -8 so you would always get 4x-8
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log(3x) = log(2x-4)
taking antilog of both sides:
3x = 2x - 4
3x - 2x = -4 [subtracting 2x from both sides]
x = -4
and we're done already!
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