A species of rodent lives in a moist forest
2 answers:
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Answer:
True
Explanation:
The linkage relation of two genes can be determined on the basis of calculating recombination frequency.
If the recombination frequency value is greater than 50% then the genes are not linked and if the value is less than 50% then the genes are linked.
In the given question, the crossover gametes formed will be Ab = 100
and aB= 106.
Therefore,
Since the recombinant frequency value is larger than 50% therefore the genes do not show linkage.
Thus, True is the correct answer.