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NikAS [45]
1 year ago
5

I’m struggling with this question need some help

Mathematics
1 answer:
Sonbull [250]1 year ago
8 0
Since the volume of a rectangular prism is V=lwh, we can isolate for h to obtain that h=V/(lw).

So, for the first prism, the height is 117/(4*6.5) = 4.5

Similarly, for the second prism, the height is 175.5/(6.5 * 4) = 6.75

So, the difference in heights is 6.75-4.5=2.25 = 2 1/4 inches
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URGENT graph the image of the given triangle after the transformation that has the rule (x, y) 》(x, -y)
crimeas [40]

Answer:

See Below

Step-by-step explanation:

That rule is a transformation across the x-axys.

Assigne a letter to each point:

A = (2, 7) => A' = (2, -7)

B = (-5, -2) => B' = (-5, 2)

C = (4, -3) => C' = (4, 3)

3 0
3 years ago
Read 2 more answers
Hey guys not good at math please help
faust18 [17]

Answer:

3/2

Step-by-step explanation:

Recall that slope is y2 - y1 / x2 - x1.

Excellent. The question provides us with two points: (2,4) and (0,1). We can insert these two points into our equation.

Slope = (4 - 1) / (2 - 0) = 3 / 2.

Hope this helps!

5 0
2 years ago
Read 2 more answers
Solve the equation.<br><br> $2v+7=3$<br><br> $v=$
stepan [7]
If your equation is 2v + 7 = 3,

Subtract 7 from both sides to get 2v = -4

Then divide 2 on both sides and get v = -4/2

Then simplify to get v = $-2
6 0
2 years ago
A football player kicks a ball with an initial upward velocity of 47 ft./s. The initial height of the ball is 3 feet. The functi
Rashid [163]

Answer: 3 seconds

We are given the following function:

h(t)=-16{t}^{2}+V.t+h(o)    (1)

Where:

t is the time the ball is in the air

V=47ft/s the initial upward velocity

h(o)=3ft the initial height of the ball

h(t) is the final height of the ball. If no one catches it, this will be <u>zero</u>

So, equation (1) changes to:

-16{t}^{2}+V.t+h(o)=0    (2)

Substituting the known values:

-16{t}^{2}+(47ft/s).t+3ft=0    (3)

This is a quadratic equation in the form a{t}^{2}+b.t+c=0. In order to find t we can use the quadratic formula for the roots:

t=\frac{-b\pm\sqrt{-4ac}}{2a}    (4)

Where a=-16, b=47 and  c=3

Substituting this values in (4):

t=\frac{-47\pm\sqrt{-4(-16)(3)}}{2(-16)}    (5)

t=\frac{-47\pm\sqrt{2401}}{-32}    (6)

t=\frac{-47\pm\49}{-32}    (7)

For t1:

t1=\frac{-47+49}{-32}=-0.0625 s      (8)>>>> This result does not work for us because is negative

For t2:

t2=\frac{-47-49}{-32}=3 s   (9)>>>This is the result

Therefore:

<h2> If no one catches the ball, it will be 3 s in the air</h2>
6 0
3 years ago
At a store Mary please $34 for 2 pounds of apples 1 pound of berries and 4 pounds of chairs Tom pays $35 for 3 pounds of apples
MrRa [10]

Answer:

34 = 2A + 1B + 4C

35 = 3A + 2B+ 2C

49 = 5A + 3B+ 2C

Pairs the 1st and 2nd equation, then eliminates C:

34 = 2A + 1B + 4C

35 = 3A + 2B + 2C

34   =  2A  +  1B + 4C

-70 = -6A + -4B + -4C  <---- multiplies 2nd equation by -2

Adds them together

-36 = -4A + -3B

36 = 4A + 3B  <----- please label this equation ALPHA

Next, pairs the 2nd and 3rd equations, and eliminates C:

35 = 3A + 2B+ 2C

49 = 5A + 3B+ 2C

Subtracts the top equation from the bottom:

49-35 = 5a-3a + 3b-2b + 2c-2c

14 = 2a + b <--- please label this equation BETA

ALPHA: 36 = 4A + 3B

BETA:   14 = 2a + b

Solves the 2x2 system by substitution:

BETA: 14 - 2a = b <---- solves equation BETA for b

Substitutes into equation ALPHA:

36 = 4a + 3(14 - 2a)

36 = 4a + 42 - 6a

36 = 42 - 2a

-6 = -2a

a=3

b = 14 - 2a = 14 - 2(3) = 14 - 6 = 8

34 = 2a + b+ 4c

34 = 2(3)+ 8 + 4c

34 = 6+8 + 4c

34 = 14 + 4c

20 = 4c

c=5

1 pound of apples cost $3

1 pound of berries cost $8

1 pound of cherries cost $5

8 0
3 years ago
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