Unfortunately, you have not shared the point through which the curve passes. Would you please do that now.
Just supposing that the graph passes through the point (2,2) (which I have invented as an example):
Write the differential equation dy/dx = 2y. Rewrite this as dy/y=2dx. Integrating both sides, ln|y|=2x+ln|c| (where c is just a constant of integration).
Solving for y: ln|y|-ln|c|=2x, or ln|y/c|=2x
then y/c=e^(2x), or y=c*e^(2x). What is the value of c? To determine this, let x=2 and y=2:
2=c*e^(2[2]) after substituting the coordinates of the point (2,2). Then
2=ce^4, or c=1/[e^4].
Substituting this c into the solution,
y= (1/[e^4])e^[2x]
This solution can be used as is, or you could try simplifying it.
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Note that if your graph goes through some point other than (2,2), the correct answer to this problem will be different.
Answer:
i dont understand this question at all
Step-by-step explanation:
<span>By translating triangle ABC 4 units up and 3 units left to form triangle A'B'C' means that the line joining each of the corresponding points represents the hypothenus of a right triangle with legs 4 units and 3 unit.
To find the length of each corresponding points, we use the prthagoras theorem which states that the square of the length of the pythagoras of a right triangle is equal to the sum of the squares of the lenght of other legs.
i.e. the square of the required distance = 4^2 + 3^2 = 16 + 9 = 25
Therefore, the distance of eachcorresponding side is given by the square root of 25 = 5.</span>
Develop two linear equations to represent the savings of these two people:
Raul: rl=$350 + $15x
Ruth: rh=$200 + $25x
In both cases, x represents the number of weeks elapsed.
When will these two people have saved up the same amount? Set rl = rh and solve for x, the number of weeks elapsed:
$350 + $15x = $200 + $25x
$150 = $10x gives us x= 15. Their savings will be equal after 15 weeks.
Answer:
2m+2m
Step-by-step explanation:
