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Serga [27]
3 years ago
15

The integral represents the volume of a solid. describe the solid. π π 0 sin(x) dx

Mathematics
1 answer:
Oxana [17]3 years ago
4 0
Is that all the question says ??
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One zero of x3 – 3x2 – 6x + 8 = 0 is -2. What are the other zeros of the function?
hram777 [196]
Consider this solution, if it is possible, check the result:
1) if to divide polynomial 'x³-3x²-6x+8' on 'x+2' result is: x²-5x+4, then x³-3x²-6x+8=(x+2)(x²-5x+4);
2) x²-5x+4=(x-1)(x-4), then
3) x³-3x²-6x+8=(x+2)(x-1)(x-4).
4) zeros are: -2;1;4. Other zeros are: 1 and 4.
Answer: 1;4.
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Penny and her two friends each ate 1/6 of cake . how much cake did they eat
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They ate 1/3 of the cake
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What’s 3/4s of 300 million
Blababa [14]
It’s 225,000,000= 225 million
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What is 65% of 80 ??????????????
bazaltina [42]

Answer:

Step-by-step explanation:

65% of 80 is

65*80/100=52

4 0
3 years ago
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For a binomial process, the probability of success is 40 percent and the number of trials is 5. Find the standard deviation.
Yakvenalex [24]

Answer:

Sd(X) =\sqrt{1.2}=1.095

Step-by-step explanation:

Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

Solution to the problem

Let X the random variable of interest, on this case we now that:

X \sim Binom(n=5, p=0.4)

The probability mass function for the Binomial distribution is given as:

P(X)=(nCx)(p)^x (1-p)^{n-x}

Where (nCx) means combinatory and it's given by this formula:

nCx=\frac{n!}{(n-x)! x!}

The mean for the binomial distribution is given by:

E(X) =np=5*0.4=2

And the variance is given by:

Var(X) = np(1-p) =5*0.4*(1-0.4)=1.2

And the deviation is just the square root of the variance so we got:

Sd(X) =\sqrt{1.2}=1.095

7 0
3 years ago
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