F(x)=2x^2-x-6
Factoring:
f(x)=2(2x^2-x-6)/2=(2^2x^2-2x-12)/2=[(2x)^2-(2x)-12]/2
f(x)=(2x-4)(2x+3)/2=(2x/2-4/2)(2x+3)→f(x)=(x-2)(2x+3)
g(x)=x^2-4
Factoring
g(x)=[sqrt(x^2)-sqrt(4)][sqrt(x^2)+sqrt(4)]
g(x)=(x-2)(x+2)
f(x)/g(x)=[(x-2)(2x+3)] / [(x-2)(x+2)
Simplifying:
f(x)/g(x)=(2x+3)/(x+2)
Answer: Third Option (2x+3)/(x+2)
This would be 8(ab) sooo yaaaa
Exactly like the previous question you posted.
-3x² - 9x = 0
Divide each side of the equation by -3 :
x² + 3x = 0
Factor the left side:
x (x + 3) = 0
This is true if x=0 or if x=-3 .
Answer:
ummm- i dont really know this one- but i think the answer is 0
Step-by-step explanation:
3x+2y=24
Times 2
6x+4y=48
-
6x+2y=30
=
2y=18
y=9
x=2. Hope it help!
