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lions [1.4K]
3 years ago
15

Algebra Nation Algebra 2 section 13 topic 4

Mathematics
2 answers:
8_murik_8 [283]3 years ago
4 0
What is the question please?
Jlenok [28]3 years ago
4 0

Answer:

What is the question? I would be happy to help you! :)

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cluponka [151]

Answer:

D

Step-by-step explanation:

5 0
2 years ago
Franchise Business Review stated over 50% of all food franchises earn a profit of less than $50,000 a year. In a sample of 130 c
nydimaria [60]

Answer:

We need a sample size of 564.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the zscore that has a pvalue of 1 - \frac{\alpha}{2}.

For this problem, we have that:

\pi = \frac{81}{130} = 0.6231

The margin of error is:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

95% confidence level

So \alpha = 0.05, z is the value of Z that has a pvalue of 1 - \frac{0.05}{2} = 0.975, so Z = 1.96.

Based upon a 95% confidence interval with a desired margin of error of .04, determine a sample size for restaurants that earn less than $50,000 last year.

We need a sample size of n

n is found when M = 0.04

So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.04 = 1.96\sqrt{\frac{0.6231*0.3769}{n}}

0.04\sqrt{n} = 1.96\sqrt{0.6231*0.3769}

\sqrt{n} = \frac{1.96\sqrt{0.6231*0.3769}}{0.04}

(\sqrt{n})^{2} = (\frac{1.96\sqrt{0.6231*0.3769}}{0.04})^{2}

n = 563.8

Rounding up

We need a sample size of 564.

4 0
3 years ago
HELP...Cant figure it out
ziro4ka [17]

Answer:44

Step-by-step explanation:

-8(-6) -4

48 -4

44

4 0
3 years ago
Multi step equation 3x+3-x+12=x+5​
dlinn [17]

Answer:

x= -10

if u need explanation pls let me know

3 0
3 years ago
Help ASAP anyone please thank you
VMariaS [17]

Answer:

D but dont get mad

Step-by-step explanation:

7 0
3 years ago
Read 2 more answers
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