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just olya [345]
2 years ago
13

Help me with this pleaseee…!

Mathematics
1 answer:
masya89 [10]2 years ago
3 0

Answer:

<u><em>All real numbers</em></u>

Step-by-step explanation:

<u><em>We can start out by knowing that</em></u><u><em> the domain of a graph is, the side, to side from the x axis directions. </em></u>

<u><em>We can see that the </em></u><u><em>line continues of the graph shown, meaning it is infinite. </em></u><u><em>Meaning the answer is </em></u><u><em>the domain is all real numbers.</em></u>

<u><em>We can double check by seeing that the other options don't work or aren't enough:</em></u>

x\geq 2\\and\\x\leq 2\\and\\x\geq -4<u><em /></u>

<u><em>The first wouldn't work becuase, yes that is part of the answer, but not the whole answer. The same goes for the others as well, they are on the line and are correct, but the best, and full answer is </em></u><u><em>"All real numbers"</em></u>

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The expression cos⁴ θ in terms of the first power of cosine is <u>[ 3 + 2cos 2θ + cos 4θ]/8.</u>

The power-reducing formula, for cosine, is,

cos² θ = (1/2)[1 + cos 2θ].

In the question, we are asked to use the formulas for lowering powers to rewrite the expression in terms of the first power of cosine cos⁴ θ.

We can do it as follows:

cos⁴ θ

= (cos² θ)²

= {(1/2)[1 + cos 2θ]}²

= (1/4)[1 + cos 2θ]²

= (1/4)(1 + 2cos 2θ + cos² 2θ] {Using (a + b)² = a² + 2ab + b²}

= 1/4 + (1/2)cos 2θ + (1/4)(cos ² 2θ)

= 1/4 + (1/2)cos 2θ + (1/4)(1/2)[1 + cos 4θ]

= 1/4 + cos 2θ/4 + 1/8 + cos 4θ/8

= 3/8 + cos 2θ/4 + cos 4θ/8

= [ 3 + 2cos 2θ + cos 4θ]/8.

Thus, the expression cos⁴ θ in terms of the first power of cosine is <u>[ 3 + 2cos 2θ + cos 4θ]/8</u>.

Learn more about reducing trigonometric powers at

brainly.com/question/15202536

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