It is 2 and 3/5 your welcome :)
Answer:
x= 5/4 ; y= -7/4
Step-by-step explanation:
I will solve your system by substitution.
(You can also solve this system by elimination.)
3x+y=2;5x−y=8
Step: Solve3x+y=2for y:
3x+y+−3x=2+−3x(Add -3x to both sides)
y=−3x+2
Step: Substitute−3x+2foryin5x−y=8:
5x−y=8
5x−(−3x+2)=8
8x−2=8(Simplify both sides of the equation)
8x−2+2=8+2(Add 2 to both sides)
8x=10
8x
8
=
10
8
(Divide both sides by 8)
x=
5
4
Step: Substitute
5
4
forxiny=−3x+2:
y=−3x+2
y=−3(
5
4
)+2
y=
−7
4
(Simplify both sides of the equation)
Answer:
x=
5
4
and y=
−7
4
Answer:
$111
Step-by-step explanation:
The bank balance is ...
$700 × (1 + 0.05) = $735
The cost of the computer is ...
$750 × (1 -0.20) × (1 +0.04) = $624
The remaining bank balance after paying for the computer is ...
$735 -624 = $111
_____
When you add a percentage, you effectively multiply by the sum of 1 and that percentage. The same is true if the amount "added" is negative (as for a discounted price).
(original amount) + (percentage)×(original amount)
Use the distributive property to factor out the original amount:
= (original amount)×(1 + percentage)
Answer:
Step-by-step explanation:
Susan started her homework at = 1:59 pm
She took time = 96 mins
Time at which she had volleyball practice = 4:00 pm
So, time between her starting of homework and starting of volleyball is given by
1:59 pm to 4:00 pm = 2 hrs and 1 mins
2 hr 1 min = 120 mins + 1 min = 121 mins
But she took 96 mins to do her homework, so
Out of 121 mins, 96 mins she took for homework
Remaining time = 121 mins - 96 mins = 25 mins
Therefore, time Susan had between finishing her homework and the beginning of volleyball practice is 25 mins
Let's call the aces 
for hearts, diamonds, clubs and spades. So, 
are red and [ted] c, s[/tex] are black.
Since the first card is replaced, the two picks are identical. This means that the sample space is given by all the possible couple
There are 16 such couples (we have four choices for the first card, and the same four choices for the second card). Now let's compute the odds in our favour to deduce the probability of winning:
If we want a player to draw two card of the same colour, the following couples are good:
so 8 possible couples over 16. This means that the probability that a player draws two cards of the same color is 8/16 = 1/2.
Similarly, the probability of drawing a red ace first and then a black ace is represented by the following couples:
which are 4 over the same 16 as above, thus leading to a probability of 4/16 = 1/4.
