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1 year ago

Expand and fully simplify 3(x + 1) + 2(3x + 4)

Mathematics

1 answer:

mrs_skeptik [129]1 year ago

4 0

Answer:

$\Large\boxed{\sf{9x+11}}$

Step-by-step explanation:

Given:

Isolate the term of x from one side of the equation.

Use the distributive property.

DISTRIBUTIVE PROPERTY:

$\Longrightarrow: \sf{A(B+C)=AB+AC}$

Each term within the parentheses can be multiplied by a factor outside the parentheses.

3(x+1)

3*x=3x

3*1=3

Rewrite the expression down.

3x+3

3x+3+2(3x+4)

Multiply expand.

2(3x+4)

2*3x=6x

2*4=8

6x+8

3x+3+6x+8

Combine like terms.

3x+6x+3+8

Add the numbers from left to right.

3+8=11

3x+6x+11

Add.

Solutions:

3x+6x=9x

$\Longrightarrow: \boxed{\sf{9x+11}}$

Therefore, the final answer is 9x+11.

I hope this helps. Let me know if you have any questions.

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garri49 [273]

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Nat2105 [25]

Answer: $\bold{9)\ \sin \theta=\dfrac{1}{3}\qquad 10)\ \sin \theta = \dfrac{4}{5}\qquad 11)\ \cos \theta = \dfrac{\sqrt{11}}{6}\qquad 12)\ \tan \theta = \dfrac{17\sqrt2}{26}}$

Step-by-step explanation:

Pythagorean Theorem is: a² + b² = c² , where "c" is the hypotenuse

$9)\ \sin \theta=\dfrac{\text{side opposite of}\ \theta}{\text{hypotenuse of triangle}}=\dfrac{4}{12}\quad \rightarrow \large\boxed{\dfrac{1}{3}}$

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Note: 12² + opposite² = 20² → opposite = 16

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Note: adjacent² + 5² = 6² → adjacent = √11

$12)\ \tan \theta=\dfrac{\text{side opposite of}\ \theta}{\text{side adjacent to}\ \theta}=\dfrac{17}{13\sqrt2}\quad =\large\boxed{\dfrac{17\sqrt2}{26}}$

Note: adjacent² + 7² = (13√2)² → adjacent = 17

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3 years ago

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