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2 years ago

Expand and fully simplify 3(x + 1) + 2(3x + 4)

Mathematics

1 answer:

mrs_skeptik [129]2 years ago

4 0

Answer:

$\Large\boxed{\sf{9x+11}}$

Step-by-step explanation:

Given:

Isolate the term of x from one side of the equation.

Use the distributive property.

DISTRIBUTIVE PROPERTY:

$\Longrightarrow: \sf{A(B+C)=AB+AC}$

Each term within the parentheses can be multiplied by a factor outside the parentheses.

3(x+1)

3*x=3x

3*1=3

Rewrite the expression down.

3x+3

3x+3+2(3x+4)

Multiply expand.

2(3x+4)

2*3x=6x

2*4=8

6x+8

3x+3+6x+8

Combine like terms.

3x+6x+3+8

Add the numbers from left to right.

3+8=11

3x+6x+11

Add.

Solutions:

3x+6x=9x

$\Longrightarrow: \boxed{\sf{9x+11}}$

Therefore, the final answer is 9x+11.

I hope this helps. Let me know if you have any questions.

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The width of a box in the shape of a rectangular prism is 4 inches more than the height h . The length is the difference of 9 in

Doss [256]

Answer:

$(a)$ $V = -H^3+ 5H^2 + 36H$

$(b)$ $Length = 5in; Width = 9in; Height = 5in$ or $Length = 3in; Width = 10in; Height = 6in$

Step-by-step explanation:

Let:

$W=Width; L = Length; H = Height$

Given

$W = 4 + H$

$L = 9 - H$

Solving (a): The polynomial for the volume in terms of height

Volume (V) is calculated using:

$V = L * W * H$

$V = (9 - H) * (4 + H) * H$

Expand

$V = (9 - H) * (4H + H^2)$

Open brackets

$V = 36H + 9H^2 - 4H^2 - H^3$

$V = 36H + 5H^2 - H^3$

Rewrite as:

$V = -H^3+ 5H^2 + 36H$

Solving (b): The dimensions when Volume = 180

Substitute 180 for V in: $V = -H^3+ 5H^2 + 36H$

$180 = -H^3+ 5H^2 + 36H$

Rewrite as:

$H^3 - 5H^2 - 36H + 180 = 0$

Factorize:

$H^2(H - 5) - 36(H - 5) = 0$

$(H^2 - 36)(H - 5) = 0$

Express $H^2 - 36$ as difference of two squares

$(H - 6)(H + 6)(H - 5) =0$

This gives:

$H - 6 =0==> H = 6$

$H + 6 =0==> H = -6$

$H - 5 =0==> H = 5$

Since the height can not be negative, then H = 5 or H = 6

Recall that:

$W = 4 + H$

$L = 9 - H$

When H = 5

$W = 4 + 5 = 9$

$L = 9 - 5 = 4$

When H = 6

$W = 4 + 6 = 10$

$L = 9 - 6 = 3$

Hence, the dimensions of the box are:

$Length = 5in; Width = 9in; Height = 5in$

$Length = 3in; Width = 10in; Height = 6in$

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Answer:

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Step-by-step explanation:

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Expand and fully simplify 3(x + 1) + 2(3x + 4)​

Expand and fully simplify 3(x + 1) + 2(3x + 4)