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BigorU [14]
2 years ago
6

Pls help me with this question​

Mathematics
2 answers:
RoseWind [281]2 years ago
8 0

Answer:

the answer is 3 and 90 that's all

Lorico [155]2 years ago
3 0
All that apply are answers A and C because the domain is referring to the min and max x values and at the height of 13 feet would be at 3 seconds
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consider a wire 2 ft long cut into two pieces. one piece forms a circle with radius r and the other forms a square with side len
makkiz [27]

The formula for the radius r in terms of x . and for the maximum areas is x=2/\pi+4

Given that,

y forms a circle of radius r

y=2\pir

r=y/2\pi

(2-y)- forms Square Side x

(2-y) = 4x

x=(2-y)/4

Now Sum of Area's=Area of Square +Area of Circle

Sum = \pir² + x²

Substitute the r and x values in above equation,

A(y)= y²/4\pi+(y-2)²/ 16

To maximize Area A(y)

A'(y)= 0

2y/4\pi + 2(y-2)/16 =0

y/2\pi + (y-2)/8 =0

y = 2\pi/\pi+4

Y max will be max, x to be maximum.

for maximum sum of areas,

x=2/\pi+4

Hence,The formula for the radius r in terms of x . and for the maximum areas is x=2/\pi+4

Learn more about Area :

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4 0
1 year ago
If you are a student with no assets of any value and have liability insurance on an old car that pays a maximum of $50,000 per a
svetoff [14.1K]

Answer:

D

Step-by-step explanation:

they will sue for the rest of the money, because they are entitled to it if you are the cause of an accident.

6 0
3 years ago
A freight train completes its journey of 150 miles 1 hour earlier if its original speed is increased by 5 miles/hour. What is th
e-lub [12.9K]
25 mph the train is accelerating at a constant rate<span />
4 0
3 years ago
Line RS intersects triangle BCD at two points and is parallel to segment DC. Triangle B C D is cut by line R S. Line R S goes th
Svetlanka [38]

Answer:

The correct options are;

1) ΔBCD is similar to ΔBSR

2) BR/RD = BS/SC

3) (BR)(SC) = (RD)(BS)

Step-by-step explanation:

1) Given that RS is parallel to DC, we have;

∠BDC = ∠BRS (Angles on the same side of transversal)

Similarly;

∠BCD = ∠BSR (Angles on the same side of transversal)

∠CBD = ∠CBD = (Reflexive property)

Therefore;

ΔBCD ~ ΔBSR Angle, Angle Angle (AAA) rule of congruency

2) Whereby  ΔBCD ~ ΔBSR, we therefore have;

BC/BS = BD/BR → (BS + SC)/BS = (BR + RD)/BR = 1 + SC/BS = RD/BR + 1

1 + SC/BS = 1 + RD/BR = SC/BS = 1 + BR/RD - 1

SC/BS = RD/BR

Inverting both sides

BR/RD = BS/SC

3) From BR/RD = BS/SC the above we have by cross multiplication;

BR/RD = BS/SC gives;

BR × SC = RD × BR → (BR)(SC) = (RD)(BR).

7 0
3 years ago
lauren bedroom is shaped like a square with sides of  six yards. what is the perimeter of that bedroom
S_A_V [24]
24, just do 6x4 because there are 4 sides.
5 0
3 years ago
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