Answer:
its probably is B. I am not sure. I wouldnt trust me though but you can if you want. ._.
Protons is the answer that makes the most sense
Given the points A and B
The coordinates of point A = ( 3 , 1 )
The coordinates of point B = (-1 , -1)
The midpoint of AB, is the point C
C will be calculated as following :
![C=\frac{A+B}{2}=\frac{(3,1)+(-1,-1)}{2}=\frac{(3-1,1-1)}{2}=\frac{(2,0)}{2}=(1,0)](https://tex.z-dn.net/?f=C%3D%5Cfrac%7BA%2BB%7D%7B2%7D%3D%5Cfrac%7B%283%2C1%29%2B%28-1%2C-1%29%7D%7B2%7D%3D%5Cfrac%7B%283-1%2C1-1%29%7D%7B2%7D%3D%5Cfrac%7B%282%2C0%29%7D%7B2%7D%3D%281%2C0%29)
so, the midpoint of AB = (1 , 0 )
C hope this helps follow me for a follow
Answer:
A choice
Step-by-step explanation:
sec is defined as 1/cos.
cos is again defined as adjacent to hypotenuse.
We know that adjacent is x and hypotenuse is r.
Therefore:- cos is x/r
Now sec is 1/cos = 1/(x/r)
1 ÷ x/r is 1•r/x
Thus:-
sec is r/x