Im pretty sure its A funding because thats alot of money
Answer:
1.67mol/L
Explanation:
Data obtained from the question include:
Mole of solute (K2CO3) = 5.51 moles
Volume of solution = 3.30 L
Molarity =?
Molarity is simply the mole of solute per unit litre of the solution. It can be expressed mathematically as:
Molarity = mole of solute /Volume of solution
Molarity = 5.51 mol/3.30 L
Molarity = 1.67mol/L
Therefore, the molarity of K2CO3 is 1.67mol/L
Answer:
The ΔHrxn for the above equation = 179 kJ/mol
Explanation:
The reaction bond enthalpies are for the reactant;
3 × N-H = 3 × 390 = 1,170 kJ/mol
2 × O=O = 2 × 502 = 1004 kJ/mol
The reaction bond enthalpies are for the product;
3 × N-O = 3 × 201 = 603 kJ/mol
3 × O-H = 3 × 464 = 1,392 kJ/mol
The ΔHrxn for the above equation is therefore;
ΔHrxn = 1,170 + 1,004 - (603 + 1,392) = 179 kJ/mol
Answer:
the relation of two different forms of the same substance (such as two allotropic forms of tin) that have a definite transition point and can therefore change reversibly each into the other — compare monotropy.
3.3 moles of sulfur
Explanation:
To find the number of moles knowing the number of atoms we use Avogadro's number to formulate the following reasoning:
if in 1 mole of sulfur (S) there are 6.022 × 10²³ atoms of sulfur (S)
then in X moles of sulfur (S) there are 2 × 10²⁴ atoms of sulfur (S)
X = (1 × 2 × 10²⁴) / (6.022 × 10²³)
X = 3.3 moles of sulfur
Learn more about:
Avogadro's number
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