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MatroZZZ [7]
3 years ago
6

How many grams of H2 will be produced from 12 grams of Mg according to the following equation?

Chemistry
1 answer:
LUCKY_DIMON [66]3 years ago
7 0

Answer:

0.98 g of H₂

Explanation:

the balanced equation for the reaction is

Mg + 2HCl ---> MgCl₂ + H₂

molar ratio of Mg to H₂ is 1:1

number of Mg moles reacted = 12 g/ 24.3 g/mol = 0.49 mol

according to molar ratio

when 1 mol of Mg reacts 1 mol of H₂ is formed

therefore when 0.49 mol of Mg reacts - 0.49 mol of H₂ forms

therefore mass of H₂ formed = 0.49 mol x 2 g/mol = 0.98 g

mass of H₂ formed is 0.98 g

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I think the answer is B.
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A gas has a volume of 5.00 L at 0°C. What final temperature, in degrees Celsius, is needed to change the volume of the gas to ea
Diano4ka-milaya [45]

Answer:

A = -213.09°C

B = 15014.85 °C

C = -268.37°C

Explanation:

Given data:

Initial volume of gas = 5.00 L

Initial temperature = 0°C  (273 K)

Final volume = 1100 mL, 280 L, 87.5 mL

Final temperature = ?

Solution:

Formula:

The given problem will be solve through the Charles Law.

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Conversion of mL into L.

Final volume = 1100 mL/1000 = 1.1 L

Final volume =  87.5 mL/1000 = 0.0875 L

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

T₂ = V₂T₁ / V₁

T₂ = 1.1 L × 273 K / 5.00 L

T₂ = 300.3 L.K / 5.00 K

T₂ = 60.06 K

60.06 K - 273 = -213.09°C

2)

V₁/T₁ = V₂/T₂

T₂ = V₂T₁ / V₁

T₂ = 280 L × 273 K / 5.00 L

T₂ = 76440 L.K / 5.00 K

T₂ = 15288 K

15288 K - 273 = 15014.85 °C

3)

V₁/T₁ = V₂/T₂

T₂ = V₂T₁ / V₁

T₂ = 0.0875 L × 273 K / 5.00 L

T₂ = 23.8875 L.K / 5.00 K

T₂ = 4.78 K

4.78 K - 273 = -268.37°C

4 0
3 years ago
What type of star has an absolute brightness of 5 and a surface temperature around 3,000 °C?
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How many moles of hydrogen gas will be produced if 5.00 moles of zinc reactions with an excess amount of sulfuric acid
harkovskaia [24]

Answer:

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Explanation:

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Limiting reagent (Zn) will decide the amount of Hydrogen produced

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