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Lina20 [59]
4 years ago
10

Jessica wants to get a credit card, but the bank is refusing to give her one. What could be the possible reason behind the bank'

s refusal to comply with Jessica's request? A. She does not have an account with the bank B. She has a bad credit history C. She has a good credit history D. She is 18 years old E. She doesn't have a job
SAT
1 answer:
tangare [24]4 years ago
7 0

Answer:

B. She has a bad credit history

Explanation:

One of the main requirements to get a credit card is to have a good credit score and this is one of the things that banks check. If someone that request a credit card has a bad credit history, the bank will refuse to give it. Because of that, the possible reason behind the bank's refusal to comply with Jessica's request is that she has a bad credit history.

The other options are not right because it is not necessary to have an account with the bank to get a credit card, a good credit history will allow you to get it, the age is not an issue and if someone doesn't have enough resources to get the card, it is possible to have a cosigner for the bank to approve it.

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Can anyone help me !!
allochka39001 [22]

Answer:

i think its B

Explanation:

If the police were giving someone a ticket it would't stop the whole traffic,  i do not believe there is enough evidence to support that a bridge fell or that the accident that happened had a teenager involved in it...

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4 years ago
suppose you push a hockey puck of mass m across frictionless ice for a time 1.0 s, starting from rest, giving the puck speed v a
saul85 [17]

Answer: Twice the previous time would be taken to reach the same speed v with the puck of mass 2m.

Explanation:

Let a Force pushes the hockey puck of mass m.

Then acceleration, a= \frac{F}{m}a=mF

From the equation of motion,

\begin{gathered}\➪ v=u+at\\ v=0+\frac{F}{m}\Delta t\end{gathered}⇒v=u+atv=0+mFΔt ......(1)

In the second case, when mass is 2m, then acceleration,

a'=\frac{F}{2m}a′=2mF

and t' is the time taken.

The final speed is v,

\begin{gathered}\➪ v=0+ a't'\\ \➪ \frac {F}{m}\Delta t=\frac{F}{2m}t'\\ \➪ t'= 2\Delta t\end{gathered}⇒v=0+a′t′⇒mFΔt=2mFt′⇒t′=2Δt using equation (1)

Hence, it would take two times the previous amount of time to push the pluck of double mass.

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