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kondor19780726 [428]
2 years ago
7

Factor the binomial. 4z2 − 25 4z2 − 25 =

Mathematics
1 answer:
svetoff [14.1K]2 years ago
6 0

4z^2-25\\\\=(2z)^2-5^2\\\\=(2z+5)(2z-5)

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the average wieght of three children a b and c is 60 lbs if another child D is included in the grouo in the place of C the avera
mars1129 [50]

The weight of the last child is 36 lbs.

<h3>How to calculate the mean?</h3>

The average weight of the three children is 60 lbs. The total weight will be:

= 60 × 3

= 180 lbs.

When another child is added, the weight is 54lb. The total weight will be:

= 54 × 4

= 216 lbs

The weight of the last child will be:

= 216 - 180

= 36 lbs.

Learn more about mean on:

brainly.com/question/1136789

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8 0
2 years ago
Simplify the expression. x^5/x^9
ryzh [129]

Answer:

1/x^4

Step-by-step explanation:

8 0
3 years ago
consider n proper fraction such that the numerator is 2 less than the denominator. If the numerator and denominator are each inc
xz_007 [3.2K]

the original fraction would be 4:5 divided by 2 and 1 making the answer clear and then what you do is take your answer multiplying it by the improper fraction and subtracting it by the mixed and the others that you should know and then you get your real answer.

Have a good day!

It might seem confusing but it is actually correct, how do i know?

 i´m a math prodigy.

3 0
3 years ago
to get on the top players’ list, don needs to have a minimum average score of 225 after playing four games. his scores on his fi
madam [21]
We know that the average is 

(192 + 214 + 250 + X)/4 = 225

then 
X = 244 
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6 0
3 years ago
Read 2 more answers
In a distribution, a score of X=60 has a z-score of -3.0.. A score of X=85 has a z-score of 2.0. What are the mean and standard
never [62]
The formula for a z-score is
z=\frac{X- \mu}{\sigma}
We don't have μ, the mean, or σ, the standard deviation.  We can, however, set up a system of two equations with the information we do have.  We know:
-3=\frac{60- \mu}{\sigma} \text{ and } 2=\frac{85- \mu}{\sigma}
We can make this look more like a "typical" system of equations by cancelling the fractional part of each equation.  We do this by multiplying the bottom of each equation by σ:
-3*\sigma=\frac{60- \mu}{\sigma}*\sigma \text{ and } 2*\sigma=\frac{85- \mu}{\sigma}*\sigma&#10;\\&#10;\\-3\sigma=60- \mu \text{ and } 2\sigma=85- \mu
Now we'll get the variables on the same side of the equation.  We'll do this by adding μ to both sides:
-3\sigma + \mu=60- \mu + \mu \text{ and } 2\sigma+ \mu =85- \mu + \mu&#10;\\&#10;\\-3\sigma+\mu=60 \text{ and } 2\sigma+\mu=85
Now we'll write this vertically:
\left \{ {{-3\sigma+\mu=60} \atop {2\sigma+\mu=85}} \right.
We will "eliminate" μ by subtracting the bottom equation:
\left \{ {{-3\sigma+\mu=60} \atop {-(2\sigma+\mu=85)}} \right. &#10;\\&#10;\\-5\sigma=-25
Divide both sides by -5:
\frac{-5\sigma}{-5}=\frac{-25}{-5}&#10;\\&#10;\\\sigma=5
Our standard deviation is 5.  Substituting this into our top equation we have:
-3(5)+μ=60
-15+μ=60
Cancel the -15 by adding it to both sides:
-15+μ+15=60+15
μ=75
Our mean is 75.
6 0
4 years ago
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