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vichka [17]
3 years ago
8

Suppose 7x+14 ice cream cones were sold on Saturday and 6x-8 were sold on sunday what is the total number of ice cream cones sol

d help me please
Mathematics
1 answer:
IrinaVladis [17]3 years ago
4 0
The answer would be 13x+6.
(7x+14)+(6x-8)
Combine like terms to get 13x+6
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Tess has 42 words of an essay typed and is typing about 1.3 words per second. Margo 122 words of an essay typed and is erasing a
scoray [572]

Answer:

  32 seconds

Step-by-step explanation:

For some number of seconds (s), Tess's essay length (t) will be ...

  t = 42 +1.3s

and Margo's essay length (m) will be ...

  m = 122 -1.2s

We will have t > m when ...

  t > m

  42 +1.3s > 122 -1.2s

  2.5s > 80 . . . . . . . . add 1.2s-42

  s > 32 . . . . . . . . . . . divide by 2.5

After 32 seconds, Tess's essay will exceed Margo's in length.

 

6 0
3 years ago
Each day, X arrives at point A between 8:00 and 9:00 a.m., his times of arrival being uniformly distributed. Y arrives independe
astraxan [27]

Answer:

Y will arrive earlier than X one fourth of times.

Step-by-step explanation:

To solve this, we might notice that given that both events are independent of each other, the joint probability density function is the product of X and Y's probability density functions. For an uniformly distributed density function, we have that:

f_X(x) = \frac{1}{L}

Where L stands for the length of the interval over which the variable is distributed.

Now, as  X is distributed over a 1 hour interval, and Y is distributed over a 0.5 hour interval, we have:

f_X(x) = 1\\\\f_Y(y)=2.

Now, the probability of an event is equal to the integral of the density probability function:

\iint_A f_{X,Y} (x,y) dx\, dy

Where A is the in which the event happens, in this case, the region in which Y<X (Y arrives before X)

It's useful to draw a diagram here, I have attached one in which you can see the integration region.

You can see there a box, that represents all possible outcomes for Y and X. There's a diagonal coming from the box's upper right corner, that diagonal represents the cases in which both X and Y arrive at the same time, under that line we have that Y arrives before X, that is our integration region.

Let's set up the integration:

\iint_A f_{X,Y} (x,y) dx\, dy\\\\\iint_A f_{X} (x) \, f_{Y} (y) dx\, dy\\\\2 \iint_A  dx\, dy

We have used here both the independence of the events and the uniformity of distributions, we take the 2 out because it's just a constant and now we just need to integrate. But the function we are integrating is just a 1! So we can take the integral as just the area of the integration region. From the diagram we can see that the region is a triangle of height 0.5 and base 0.5. thus the integral becomes:

2 \iint_A  dx\, dy= 2 \times \frac{0.5 \times 0.5 }{2} \\\\2 \iint_A  dx\, dy= \frac{1}{4}

That means that one in four times Y will arrive earlier than X. This result can also be seen clearly on the diagram, where we can see that the triangle is a fourth of the rectangle.

6 0
3 years ago
What is cos (x)?<br><br> 48/58<br><br> 58/48<br><br> 26/58<br><br> 58/26
Evgen [1.6K]
<span>We have to calculate the length of the missing side.
Use the Pythagorean theorem:

a^2+32^2=58^2\\\\a^2+1024=3364\ \ \ |-1024\\\\a^2=2340\to a=\sqrt{2340}\\\\a=\sqrt{36\cdot65}\\\\a=6\sqrt{65}

\cos x=\dfrac{6\sqrt{65}}{58}=\dfrac{3\sqrt{65}}{29}

I think. Your answers to choice are wrong.
</span>
8 0
3 years ago
Need help with number 9
beks73 [17]

Step-by-step explanation:

v=6t-6

integrating

s= 3t^2 -6t +k

5=3(1)^2 -6(1) +k

5-3+6=k

k=8

s(t) = 3t^2 -6t +8

7 0
2 years ago
PLEASSSSEEEE HELP ASAP
Scorpion4ik [409]

Answer:

B

Step-by-step explanation:

the dog was coming near.

6 0
3 years ago
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