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Nina [5.8K]
2 years ago
13

How is the pressure of a gas related i it’s concentrated of particles

Physics
1 answer:
fenix001 [56]2 years ago
4 0

Answer:

Las moléculas de un gas se mueven a gran velocidad, chocando contra las paredes del recipiente que las contiene, estos choques causan la presión que ejerce el gas. Sí se aumenta el volumen en el que el gas está contenido, disminuye el número de choques moleculares sobre la pared y consecuentemente la presión.

Explanation:

Las moléculas de un gas se mueven a gran velocidad, chocando contra las paredes del recipiente que las contiene, estos choques causan la presión que ejerce el gas. Sí se aumenta el volumen en el que el gas está contenido, disminuye el número de choques moleculares sobre la pared y consecuentemente la presión.

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Two points are on a disk turning at constant angular velocity. One point is on the rim and the other halfway between the rim and
DerKrebs [107]

Answer:

The point on the rim

Explanation:

All the points on the disk travels at the same angular speed \omega, since they cover the same angular displacement in the same time. Instead, the tangential speed of a point on the disk is given by

v=\omega r

where

\omega is the angular speed

r is the distance of the point from the centre of the disk

As we can see, the tangential speed is directly proportional to the distance from the centre: so the point on the rim, having a larger r than the point halway between the rim and the axis, will have a larger tangential speed, and therefore will travel a greater distance in a given time.

3 0
4 years ago
Jason throws a ball horizontally off a 300 meter cliff at 15.0 m/s. How far will it travel before it hits the
jasenka [17]

Answer:

117,30m

Explanation:

I think the situation here is a horizontal projection to the ground. So in order to find the distance the formula = Ut, where U is the initial speed and t is the Time of flight. To get the time of flight in this case =√2h/g where h is the height and g is gravity. so to get the time = √2×300÷9.81 =7.821 .so range =ut which is equal to the time multiplied by 15m/s =117.30m

8 0
3 years ago
Read 2 more answers
An electron is accelrated by a unifor electric field (1000v/m) pointing vertically upward. Use energy methods to get the magnitu
ExtremeBDS [4]

Explanation:

In the given situation two forces are working. These are:

1) Electric force (acting in the downward direction) = qE

2) weight (acting in the downward direction) = mg

Therefore, work done by all the forces = change in kinetic energy

Hence, qE \times S + mg \times S = 0.5 \times mv^{2}

     1.6 \times 10^{-19} \times 1000 + 9.1 \times 10^{-31} \times 9.8 \times (\frac{0.10}{100}) = 0.5 \times 9.1 \times 10^{-31} \times v^{2}

It is known that the weight of electron is far less compared to electric force. Therefore, we can neglect the weight  and the above equation will be as follows.

   (1.6 \times 10^{-19} \times 1000) \times (\frac{0.10}{100}) = 0.5 \times 9.1 \times 10^{-31} \times v^{2
}

         v = sqrt{\frac{1.6 \times 10^{-19}}{(0.5 \times 9.1 \times 10^{-31})}

           = 592999 m/s

Since, the electron is travelling downwards it means that it looses the potential energy.

8 0
3 years ago
What is the net force on a refrigerator that you push with an applied force of 125 N to the right and the (sliding) friction bet
lina2011 [118]

Answer:

hola

Explanation:

jffkbjkcvncncjcncjcjchchchcjcjcjcjcjckgmndjekbm hdfstfm mvndbfncn bdhwhgmvmch

8 0
3 years ago
You stand on a straight desert road at night and observe a vehicle approaching. This vehicle is equipped with two small headligh
zhuklara [117]

Complete Question

You stand on a straight desert road at night and observe a vehicle approaching. This vehicle is equipped with two small headlights that are 0.681 m apart. At what distance, in kilometres, are you marginally able to discern that there are two headlights rather than a single light source?Take the wavelength of the light to be 549 nm and your pupil diameter as 4.63 mm.  

Answer:

The distance is  z  = 4707.6 \ m

Explanation:

From the question we are told that

    The is distance between the headlight is d = 0.681 \ m

   The wavelength is  \lambda = 549 \ nm = 549 *10^{-9} \ m

    The  pupil diameter is  D  = 4.63 \ mm = 0.00463 \ m

Generally, we can mathematically evaluate the resolution of the eye as

            \theta  = \frac{1.22 *  \lambda }{D}

    substituting values

              \theta  = \frac{1.22 *  549 *10^{-9} }{0.00463}

              \theta  =  (1.45 *10^{-4} )^o

Now according to SOHCAHTOA rule  

         sin \theta  =  \frac{ d}{z}

Where z is  the distance at which the eye can discern the two head light

  given that the angle is very small sin \theta =  \theta

=>    \theta  =  \frac{ d}{z}

substituting values

     1.45*10^{-4}  =  \frac{ 0.681}{z}

=>   z  = \frac{0.681}{1.45 *10^{-4}}

=>    z  = 4707.6 \ m

   

6 0
4 years ago
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