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Advocard [28]
2 years ago
8

Find the total cost of an $849.50 laptop after including 6% sales tax.

Mathematics
2 answers:
ludmilkaskok [199]2 years ago
8 0

Answer:

$900.47

Step-by-step explanation:

you minus $50.47 (%6) from $900.47

SpyIntel [72]2 years ago
6 0
I believe the answer is $900.47
To find percentage easy make it decimal. Mice decimal twice to the right of the number, and multiply by what you want a percentage of. Add that to original number for this problem.
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Doug mcdougal is whipping up 72 different snacks for his 12th annual blooper bowl bash he invited 138 guess but only 16 are comi
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The number of guests coming to Doug McDougal party can be calculated to be 23 people.

<h3>What number of people are coming?</h3>

Doug invited 138 guests and out of this, only 1/6 will be coming.

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1 year ago
What is 1/9 - 2 4/9 - 5/9
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1/9-22/9-5/9
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3 years ago
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Scott and Letitia are brother and sister. After dinner, they have to do the dishes, with one washing and the other drying. They
ehidna [41]

Answer:

The probability that Scott will wash is 2.5

Step-by-step explanation:

Given

Let the events be: P = Purple and G = Green

P = 2

G = 3

Required

The probability of Scott washing the dishes

If Scott washes the dishes, then it means he picks two spoons of the same color handle.

So, we have to calculate the probability of picking the same handle. i.e.

P(Same) = P(G_1\ and\ G_2) + P(P_1\ and\ P_2)

This gives:

P(G_1\ and\ G_2) = P(G_1) * P(G_2)

P(G_1\ and\ G_2) = \frac{n(G)}{Total} * \frac{n(G)-1}{Total - 1}

P(G_1\ and\ G_2) = \frac{3}{5} * \frac{3-1}{5- 1}

P(G_1\ and\ G_2) = \frac{3}{5} * \frac{2}{4}

P(G_1\ and\ G_2) = \frac{3}{10}

P(P_1\ and\ P_2) = P(P_1) * P(P_2)

P(P_1\ and\ P_2) = \frac{n(P)}{Total} * \frac{n(P)-1}{Total - 1}

P(P_1\ and\ P_2) = \frac{2}{5} * \frac{2-1}{5- 1}

P(P_1\ and\ P_2) = \frac{2}{5} * \frac{1}{4}

P(P_1\ and\ P_2) = \frac{1}{10}

<em>Note that: 1 is subtracted because it is a probability without replacement</em>

So, we have:

P(Same) = P(G_1\ and\ G_2) + P(P_1\ and\ P_2)

P(Same) = \frac{3}{10} + \frac{1}{10}

P(Same) = \frac{3+1}{10}

P(Same) = \frac{4}{10}

P(Same) = \frac{2}{5}

8 0
3 years ago
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