29. Mr. Ignado gave 4 orange erasers and 5 green erasers to each of the

Mathematics

1 answer:

dangina [55]2 years ago

6 0

One hundred and eighty erasers

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The mass of the Earth is 5.972x10^24 kg. the mass of the moon is 7.3 x 10^22kg. find the total mass, in kg, of the Earth and the

torisob [31]

Answer:

6045000000000000000000000 kg.

Step-by-step explanation:

We have been given that the mass of Earth is $5.972\times10^{24}$ kg. The mass of the Moon is $7.3\times10^{22}$ kg.

To find the total mass we will add mass of Earth and Moon.

First of all let us convert the given masses in standard form.

$5.972\times10^{24}=5972000000000000000000000$

$7.3\times10^{22}=73000000000000000000000$

$5.972\times10^{24}+7.3\times10^{22}$

$5972000000000000000000000+73000000000000000000000$

$6045000000000000000000000$

Therefore, the mass of Earth and Moon is 6045000000000000000000000 kg.

8 0

3 years ago

If the starting time is 7:43 and the elapsed time is 36 minutes then what time what is the ending time

Annette [7]

Answer:

8:19

Step-by-step explanation:

It is 17 minutes until 8:00. 36 - 17 = 19 minutes left.

8:00 + 19 minutes = 8:19

6 0

3 years ago

Read 2 more answers

Solve the equation on the interval [0, 2pi): 12cos^2 x-9=0<br><br><br> What to do?

siniylev [52]

Answer:

$\large\boxed{x=\dfrac{\pi}{6}\ \vee\ x=\dfrac{5\pi}{6}\ \vee\ x=\dfrac{7\pi}{6}\ \vee\ x=\dfrac{11\pi}{6}}$

Step-by-step explanation:

$12\cos^2x-9=0\qquad\text{add 9 to both sides}\\\\12\cos^2x=9\qquad\text{divide both sides by 12}\\\\\cos^2x=\dfrac{9}{12}\\\\\cos^2x=\dfrac{9:3}{12:3}\\\\\cos^2x=\dfrac{3}{4}\to\cos x=\pm\sqrt{\dfrac{3}{4}}\\\\\cos x=\pm\dfrac{\sqrt3}{2}\\\\\text{Look at the picture}\\\\x=\dfrac{\pi}{6}\ \vee\ x=\dfrac{5\pi}{6}\ \vee\ x=\dfrac{7\pi}{6}\ \vee\ x=\dfrac{11\pi}{6}$