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2 years ago

You want to take a trip to the beach, which costs $450. You

Mathematics

1 answer:

poizon [28]2 years ago

7 0

Answer:

900 - 60n ≥ 450

n ≤ 7.5

Answer: 7 weeks

Step-by-step explanation:

Let n = numberof weeks.

In n weeks, you withdraw 60n from the account.

After withdrawing $60 for n weeks, teh amount must be at least $450. At least $450 means greater than or equal to $450.

900 - 60n ≥ 450

-60n ≥ -450

n ≤ 7.5

Answer: 7 weeks

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Which of the following is the surface area of the right cylinder below?

Norma-Jean [14]

Answer: (A) 352 π units^2
Explanation in image.

Knowledge point:
Geometry - cylinder area formula

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2 years ago

Solve for q. 3(q − 7) = 27 q =

Whitepunk [10]

Answer:

The answer is, q = 16.

Step-by-step explanation:

1) Divide both sides by 3.

$q - 7 = \frac{27}{3}$

2) Simplify 27/3 to 9.

$q - 7 = 9$

3) Add 7 to both sides.

$q = 9 + 7$

4) Simplify 9 + 7 to 16.

$q = 16$

Therefor, the answer is q = 16.

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3 years ago

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Lua is creating a rectangular prism the base of her prism is shown below she plans to have a height of 7 cubes

tresset_1 [31]

Answer:

Step-by-step explanation:

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3 years ago

1st Step: 3 - 4x - 7 = -24 2nd Step: 3- 7 - 4x = -24 What property justifies the 2nd step

gizmo_the_mogwai [7]

Answer:

the subtraction

Step-by-step explanation:

3 0

3 years ago

Given that Cosecant (t) = negative StartFraction 13 Over 5 EndFraction for Pi less-than t less-than StartFraction 3 pi Over 2 En

Sergio [31]

Answer:

$\bold{cot(t) =\dfrac{12}{5}}$

Step-by-step explanation:

Given that:

$Cosec (t) = -\frac{13}5$

for $\pi < t < \frac{3 \pi}2$

That means, angle $t$ is in the 3rd quadrant.

To find:

Value of cot(t)

Solution:

First of all, let us recall what trigonometric ratios are positive and what trigonometric ratios are negative in 3rd quadrant.

In 3rd quadrant, tangent and cotangent are positive.

All other trigonometric ratios are negative.

Let us have a look at the following identity:

$cosec^2\theta -cot^2\theta =1$

here, $\theta =t$

So, $cosec^2t-cot^2t=1$

$\Rightarrow (-\dfrac{13}{5})^2-cot^2t=1\\\Rightarrow (\dfrac{169}{25})-cot^2t=1\\\Rightarrow \dfrac{169}{25}-1=cot^2t\\\Rightarrow \dfrac{169-25}{25}=cot^2t\\\Rightarrow \dfrac{144}{25}=cot^2t\\\Rightarrow cot(t)=\pm\sqrt{\dfrac{144}{25}}\\\Rightarrow cot(t)=\pm\dfrac{12}{5}$

But, angle $t$ is in 3rd quadrant, so value of

$\bold{cot(t) =\dfrac{12}{5}}$

4 0

3 years ago