Answer:
a) 
b) 
Step-by-step explanation:
a) 
1. Distribute the second power (2) outside the first pair of parenthesis:

= 
2. Distribute the third power (3) outside the second pair of parenthesis:

= 
3. Combine like terms:

--------------------------------------------
b) 
1. Factor the number 6 (= 2 · 3):

2. Cancel the common factor (2):

3. Cancel out
in the numerator an denominator:

hope this helps!
<h3>
Answer: 5 < x < 29</h3>
=========================================
Explanation:
Since AB is smaller than AD, this must mean the angle ACB is smaller than angle ACD. Note how these angles are opposite the sides mentioned.
So 2x-10 < 48
At the same time, 2x-10 is also larger than 0.
Overall, we can say 0 < 2x-10 < 48
---------
Let's solve for x
0 < 2x-10 < 48
0+10 < 2x < 48+10 ...... add 10 to all sides
10 < 2x < 58
10/2 < x < 58/2 ..... divide all sides by 2
5 < x < 29
Length of the arc = radius x θ = 8 x 45 x π/180
= 8 x π/4 = 2π = 6.28 in ~ 6.3 in
Answer
Fill the 5 gallon jug.
Pour the 5 gallon jug into the 3 gallon jug.
Empty the 3 gallon jug and pour the remaining 2 gallons in the 3 gallon jug.
Fill the 5 gallon jug and pour 1 gallon into the 3 gallon jug (remember it will only take one gallon)
Viola the remaining 5 gallon jug will have exactly 4 gallons remaining.