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3 years ago

0.932 g = ----------- mg

Mathematics

2 answers:

rewona [7]3 years ago

4 0

Answer:

932 mg

Step-by-step explanation:

Brut [27]3 years ago

3 0

Answer:

932

Step-by-step explanation:

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Simplify square root of 2 over cube root of 2.

Fed [463]

Answer:

2 to the power of one sixth

Step-by-step explanation:

Assuming you don't already know this, any type of root can be expressed as an exponent. Generally speaking:

$\sqrt[n]{x} = {x}^{ \frac{1}{n} }$

So you can rewrite the given fraction as

$\frac{ {2}^{ \frac{1}{2} } }{ {2}^{ \frac{1}{3} } }$

and then reduce as you normally would. That is, if the bases of the numerator and denominator are the same, then you can subtract the denominator's exponent from the numerator's exponent like so:

$\frac{ {2}^{ \frac{1}{2} } }{ {2}^{ \frac{1}{3} } } = {2}^{ \frac{1}{2} - \frac{1}{3} }$

Since

$\frac{1}{2} - \frac{1}{3} = \frac{3}{6} - \frac{2}{6} = \frac{1}{6}$

the answer is

${2}^{ \frac{1}{6} } \: or \: \sqrt[6]{2}$

3 0

3 years ago

Read 2 more answers

Simplify the expression. (3.14×107)×(1.3×10−3)÷0.2<br> Scientific notation PLS!

marusya05 [52]

$3.14 \times 107 = 335.98$
$(335.98) \times (1.3 \times 10 - 3) \div 0.2$
$1.3 \times 10 = 13 - 3 = 10$
$(335.98) \times (10) \div 0.2$
$335.98 \times 10 = 3359.8$
$3359.8 \div 0.2 = 16799$
$1.6799 \times {10}^{4}$

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3 years ago

What is four blank four blank four equals 4

attashe74 [19]

4 - 4 + 4 = 4.
four minus for plus four equals four.

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3 years ago

Tom is 45 and pays $2042 on his mortgage each month while his total take home pay is $5950 per month. The national average, for

Scrat [10]

Take the amount that he pays for his mortgage, so $2042, and divide that by his total pay, $5950. You’ll get .34016907. Then to make a decimal into a percentage, you multiply it by 100. This gives you 34%, meaning he spends less than the national average on housing.

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3 years ago

If f (n)(0) = (n + 1)! for n = 0, 1, 2, , find the taylor series at a=0 for f.

Pie

Given that $f^{(n)}(0)=(n+1)!$ , we have for $f(x)$ the Taylor series expansion about 0 as

$f(x)=\displaystyle\sum_{n=0}^\infty\frac{(n+1)!}{n!}x^n=\sum_{n=0}^\infty(n+1)x^n$

Replace $n+1$ with $n$ , so that the series is equivalent to

$f(x)=\displaystyle\sum_{n=1}^\infty nx^{n-1}$

and notice that

$\displaystyle\frac{\mathrm d}{\mathrm dx}\sum_{n=0}^\infty x^n=\sum_{n=1}^\infty nx^{n-1}$

Recall that for $|x|$ , we have

$\displaystyle\sum_{n=0}^\infty x^n=\frac1{1-x}$

which means

$f(x)=\displaystyle\sum_{n=1}^\infty nx^{n-1}=\frac{\mathrm d}{\mathrm dx}\frac1{1-x}$
$\implies f(x)=\dfrac1{(1-x)^2}$

5 0

3 years ago

0.932 g = ----------- mg​

0.932 g = ----------- mg