Solve the equation sin theta = .3 to the nearest tenth. Use the restrictions 90 < theta <180
1 answer:
Sinα=3/10
α=arcsin(3/10)°
α≈17.5°
But since we are restricted to 90°<α<180° the angle must lie in the second quadrant so:
α≈(180-17.5)°
α≈162.5°
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