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harkovskaia [24]
3 years ago
11

Drag the simplified value into the box to match each expression.

Mathematics
1 answer:
AveGali [126]3 years ago
4 0

Answer:

2^{3} +1⋅4−3 = 9

2^{0}+10−4⋅2 = 3

3+5^{2} -6⋅4 = 4

Step-by-step explanation:

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Round to the nearest tenth 19.95
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Answer:

20

Step-by-step explanation:

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1.The height and radius are the same in both cylinders. Which cylinder has the greatest volume?
natulia [17]
Problem One
This is one of those questions that you might think is silly until you try it for yourself or you read about it.

The thing you have to understand, which is not well stated, is that oblique cylinders have circles on the top and bottom. You guys (in the United States) still have pennies, don't you? Take 10 or twelve of them and  make a stack where each penny sticks out 1/16 of an inch from the edge of the penny below it. I can't draw it I don't think (even my stick men look like someone who can't hold a pencil drew them), but maybe I can find a picture or you can. 


Got it. 

So the oblique cylinder has a circle on the top and bottom, just the way the pennies do when you stack them like the cylinder below. Then you can stack them like a soup can. Did anything change? No

The correct answer is (drum roll please) <<<<<<< <em>They are the same volume.


</em>Problem 2
<em />Suppose you have a glass whose sides are straight up and down (a right cylinder with no top). You fill the glass with water. Stop a moment to consider this. Now magically  you place a plain right through the middle of the glass. 

Question: is there any difference between the shape of the plain at the top of the glass than that shape at the middle? (You should answer that they are the same shape -- a circle --  at both the top and middle of the glass).

If you caught on, you would have said that the shapes are the same in your question.

Hexagon <<<<<<<<<< answer.

7 0
3 years ago
Solve for x ~<br><br><img src="https://tex.z-dn.net/?f=%5Cbold%5Cpink%7Bx%20%7B%7D%5E%7B2%7D%20%2B%205x%20-%206%20%3D%200%7D" id
Troyanec [42]

\qquad \qquad \rm \large \dag  \: Answer  \: \dag

We have been given a Quadratic equation, where we have to find the real values of x ~

So, let's proceed with middle term splitting method :

\qquad \sf  \dashrightarrow \:  {x}^{2}  + 5x - 6 = 0

\qquad \sf  \dashrightarrow \:  x {}^{2}  + 6x - x - 6 = 0

\qquad \sf  \dashrightarrow \:  {x(}^{} x + 6) - 1(x + 6) = 0

\qquad \sf  \dashrightarrow \: (x + 6)(x - 1) = 0

Now, we have two conditions here~

Either (x + 6) = 0

\qquad \sf  \dashrightarrow \: x =  - 6

or (x - 1) = 0

\qquad \sf  \dashrightarrow \: x = 1

4 0
2 years ago
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