Y = mx + b
slope(m) = -1/3
(4,-2)...x = 4 and y = -2
sub and find b, the y int
-2 = -1/3(4) + b
-2 = -4/3 + b
-2 + 4/3 = b
-6/3 + 4/3 = b
-2/3 = b
so ur equation is : y = -1/3x - 2/3....or x + 3y = -2
ur y int is (0,-2/3)....ur x int is (-2,0)...ur slope is -2/3....other points on ur line include (1,-1) , (4,-2) , (7,-3), (10,-4), (-5,1), (-8,2)...plot these points...u should be able to see ur line from this
Answer: x=2.5, and x-1=1.5
Step-by-step explanation:
x + 3 = 3x - 1
(-x)= 3 = 2x - 1
(÷2) = 1.5 = x - 1
(+1)= 2.5 = x
Answer:
y = 2/3x - 1
Step-by-step explanation:
The simpliest way to determine the slope of the line is to see the rise over run of the line. In this case, we are given two points which are at (0, -1) and (3,1)
By calculating rise of run, we can see that the starting point goes up by 2 units, from -1 to 1 and goes to the right 3 units, from 0 to 3
In this case, that means we have a slope of 2/3x.
The +b plays into the y-intercept of the line, which is actually the same of one of our points: (0,-1)
Since this number is a negative, it would actually be y = (2/3)x + (-1) which is the same as y=2/3x - 1
