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frosja888 [35]
3 years ago
9

I WILL GIVE 20 POINTS TO THOSE WHO ANSWER THIS QUESTION RIGHT NOOOO SCAMS AND EXPLAIN WHY THAT IS THE ANSWER

Mathematics
1 answer:
Leviafan [203]3 years ago
7 0

\qquad\qquad\huge\underline{{\sf Answer}}

\textbf{Since it's a right angled Triangle we can }  \\ \textbf{ use Pythagoras theorem }

  • \sf{Cos (29°) = \dfrac{b}{c}}

  • \sf{Cos (29°) = \dfrac{b}{260}}

  • \sf{b= 260\cdot Cos (29°) }

  • \sf{b= 260\cdot 0.875 }

[ \textsf{Cos(29°)= 0.875} ]

  • \sf{b= 227.5 in }

\textsf{I hope you understood the procedure}

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If the heights of 300 students are normally distributed with mean 68.0 inches and standard deviation 3.0 inches, how many studen
Lunna [17]
Given:
μ = 68 in, population mean
σ = 3 in, population standard deviation

Calculate z-scores for the following random variable and determine their probabilities from standard tables.

x = 72 in:
z = (x-μ)/σ = (72-68)/3 = 1.333
P(x) = 0.9088

x = 64 in:
z = (64 -38)/3 = -1.333
P(x) = 0.0912

x = 65 in
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For x > 72 in, obtain
300 - 300*0.9088 = 27.36

Answer: 27

Part (b)
For x ≤ 64 in, obtain
300*0.0912 = 27.36

Answer: 27

Part (c)
For 65 ≤ x ≤ 71, obtain
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3 0
3 years ago
The base of a right pyramid is a regular hexagon with sides of length 12 m. The altitude is 6 m. Find the total surface area of
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Answer:

806.12 m

Step-by-step explanation:

<u>Step 1: Write the data</u>

<em>Side (s) = 12</em>

<em>Altitude (h) = 6</em>

<u>Step 2: Write the formula for surface area of right hexagonal pyramid</u>

<em>Area = 3√3/2*s² + 3*s*√(h²+3s²/4)</em>

<u>Step 3: Substitute values of 's' and 'h'</u>

<em>Area = 3√3/2*(12)² + 3*(12)*√[6²+3(12)²/4]</em>

Area = 806.12 m

Therefore, the total surface area of the pyramid is 806.12 m.

!!

4 0
3 years ago
What is the equation of this line?<br> Y= 2x - 3<br> y=-x-3y = -2x - 3<br> y = x - 3
kobusy [5.1K]

Answer: y=2x-3

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It will cross the y axis at -3 and the x axis at 3/2

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