There are two triangular faces and three rectangular faces.
The triangular faces are congruent, so they have the same area. We calculate one and we'll know both.
The three rectangles are different.
Triangular face (each)
Although you can hardly see in the colored figure, there is a small symbol on the right side showing that the 4 km side and the 3 km side of the triangles are perpendicular. That means those sides are the base and the height.
A = (1/2)bh = (1/2)(3 km)(4 km) = 6 km^2
Rectangular faces:
A = LW = 7 km * 3 km = 21 km^2
A = LW = 7 km * 5 km = 35 km^2
A = LW = 7 km * 4 km = 28 km^2
total surface area = 2 * 6 km^2 + 21 km^2 + 35 km^2 + 28 km^2
total surface area = 96 km^2
The difference between the coefficients 7 and 3 is 4, so one solution is
y = 1, x = -1.
Then the remaining solutions will be of the form
x = -7n-1
y = 3n+1
for some integer n.
_____
Some of the solutions are (for n=0, -1, -2, 1, 2)
(x, y) = (-1, 1), (6, -2), (13, -5), (-8, 4), (-15, 7)
there are 16 ounces in a pound so 16x7=112 +2= 114
Answer:
9
Step-by-step explanation:
You gave the answer right in your question
Answer:
Step-by-step explanation:
Given the equation of motion;
S = ut + 1/2 at² where;
u is the initial velocity,
a is the acceleration, and;
t is the time.
We are to express a in terms of u, t and S
Making a the subject of the formula;
S = ut + 1/2 at²
S-ut = 1/2at²
2(S-ut) = at²
a = 2(S-ut)/t²
Hence the acceleration a in terms of other variables is expressed as a = 2(S-ut)/t²
