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2 years ago

What is the surface area of the prism?

Mathematics

2 answers:

serg [7]2 years ago

6 0

520 m²

Here given:

length: 10 m
width: 8 m
height: 10 m

surface area of rectangular prism:

2(lw+hw+hl)

2(10*8+10*8+10*10)

2(80+80+100)

2(260)

520 m²

Nady [450]2 years ago

4 0

Answer:

Surface Area = 520 m² ( Option C is correct )

Step-by-step explanation:

In this question we are given a rectangular prism which having :

Length = 10 m

Width = 8 m

Height = 10 m

And we are asking to find the surface area of prism . We know that ,

$\blue{ \underline{ \boxed{ \sf{Surface \: Area_{(Rectangular \: Prism)} =2(lw + wh + hl )}}}}$

Where ,

l = Length of prism

w = Width of prism

h = Height of prism

Solution : -

Now solving by substituting value of length, width and height in the formula . So ,

$\longmapsto \quad \: 2( (10 \times 8 )+ (8 \times 10) + (10 \times 10))$

$\longmapsto \quad \:2(80 + 80 + 100)$

$\longmapsto \quad \:2(160 + 100)$

$\longmapsto \quad \:2(260)$

$\longmapsto \quad \: \underline{\boxed{\frak{520 \: m {}^{2} }}}$ ✦

Henceforth, surface area of given prism is 520 square metres which means option C is the correct answer .

<h2>#Keep Leaning</h2>

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Eric Drew an obtuse triangle. Which of the following could be true for Eric's triangle.

Vika [28.1K]

Answer:

Option:B is the correct answer.

B: possible angle measures of the triangle are 92, 48, and 40 .

Step-by-step explanation:

We know that an obtuse triangle is a triangle whose one angle is a obtuse angle ( i.e. the measure of the angle is greater than 90 degree and less than 180 degrees).

A: all three angles have equal measures

Let the angle of a triangle be 'x'.

As we know that the sum of all the angles of a triangle is 180°.

This implies that:

x+x+x=180°

3x=180°

⇒ x=60°

Hence, the triangle will not be obtuse as none of the angle is obtuse.

Hence, option: A is incorrect.

possible angle measures of the triangle are 92, 48, and 40.

This option is correct.

Since there is one angle which is obtuse ( measure 92 degree)

and also such a angle measure is possible in a triangle as sum of all the angles is 180°.

( since 92+48+40=180°)

two of the angles are equal, and the third angle has a measure of 70.

Let the equal angles be represented by 'x'.

As the sum of all the angles is 180°.

⇒ x+x+70=180°

⇒ 2x=110°

⇒ x=55°

Hence, here also none of the angle is obtuse.

hence, option: C is incorrect.

One angle has a measure of 90, while, the other two angles measure less than 90°.

Such a triangle will not be a obtuse triangle as none of the angle measure is greater than 90°.

Hence, option: D is incorrect.

4 0

3 years ago

I don't know I try my best I'm not good at this

AlladinOne [14]

You should definitely ask your parents or teacher. Also, never give up :)
Trust me just keep trying your best and don't tell yourself that you can't do it :)

8 0

3 years ago

Consider writing onto a computer disk and then sending it through a certifier that counts the number of missing pulses. Suppose

Furkat [3]

Answer:

a) 0.164 = 16.4% probability that a disk has exactly one missing pulse

b) 0.017 = 1.7% probability that a disk has at least two missing pulses

c) 0.671 = 67.1% probability that neither contains a missing pulse

Step-by-step explanation:

To solve this question, we need to understand the Poisson distribution and the binomial distribution(for item c).

Poisson distribution:

In a Poisson distribution, the probability that X represents the number of successes of a random variable is given by the following formula:

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}
$

In which

x is the number of sucesses

$
e = 2.71828$ is the Euler number

$\mu$ is the mean in the given interval.

Binomial distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Poisson mean:

$\mu = 0.2$

a. What is the probability that a disk has exactly one missing pulse?

One disk, so Poisson.

This is P(X = 1).

$P(X = 1) = \frac{e^{-0.2}*0.2^{1}}{(1)!} = 0.164
$

0.164 = 16.4% probability that a disk has exactly one missing pulse

b. What is the probability that a disk has at least two missing pulses?

$P(X \geq 2) = 1 - P(X < 2)$

In which

$P(X < 2) = P(X = 0) + P(X = 1)$

In which

$P(X = x) = \frac{e^{-\mu}*\mu^{x}}{(x)!}
$

$P(X = 0) = \frac{e^{-0.2}*0.2^{0}}{(0)!} = 0.819$

$P(X = 1) = \frac{e^{-0.2}*0.2^{1}}{(1)!} = 0.164
$

$P(X < 2) = P(X = 0) + P(X = 1) = 0.819 + 0.164 = 0.983$

$P(X \geq 2) = 1 - P(X < 2) = 1 - 0.983 = 0.017$

0.017 = 1.7% probability that a disk has at least two missing pulses

c. If two disks are independently selected, what is the probability that neither contains a missing pulse?

Two disks, so binomial with n = 2.

A disk has a 0.819 probability of containing no missing pulse, and a 1 - 0.819 = 0.181 probability of containing a missing pulse, so $p = 0.181$

We want to find P(X = 0).

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{2,0}.(0.181)^{0}.(0.819)^{2} = 0.671$

0.671 = 67.1% probability that neither contains a missing pulse

8 0

3 years ago

I cant figure this one out at all

eduard

Answer:

a. 2^(x-2) = g^(-1)(x)

b. A, B, D

Step-by-step explanation:

the phrasing attached in the image is flagged as inappropriate, so i will be replacing it with g(x) and its inverse with g^(-1)(x)

1. replace g(x) with y and solve for x

y = log₂(x) + 2

subtract 2 from both sides to isolate the x and its log

y - 2 = log₂(x)

this text is replaced by the second image -- it was marked as inappropriate

thus, 2^(y-2) = x

replace x with g^(-1)(x) and y with x

2^(x-2) = g^(-1)(x)

2. plug this in to points A, B, C, D, E, and F

A: (2,1)

plug 2 in for x

2^(2-2) = 2⁰ = 1 so this works

B: (4, 4)

2^(4-2) = 2²= 4 so this works

C: (9, 3)

2^(9-2) = 2⁷ = 128 ≠ 3 so this doesn't work

(5, 8)

2^(5-2) = 2³ = 8 so this works

E: (3, 5)

2^(3-2) = 2¹ = 2 ≠ 5 so this doesn't work

F: (8, 5)

2^(8-2) = 2⁶ = 64 ≠ 5 so this doesn't work

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2 years ago

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3 years ago