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arlik [135]
2 years ago
14

A random sample of adult female reaction times has a sample mean of x¯=394.3 milliseconds and sample standard deviation of s=84.

6 milliseconds. Use the Empirical Rule to determine the approximate percentage of adult female reaction times that lie between 140.5 and 648.1 milliseconds.
Round your answer to the nearest tenth.
Mathematics
1 answer:
s2008m [1.1K]2 years ago
8 0

Answer:

99.7%

Step-by-step explanation:

Given that mean (μ) = 394.3 ms and standard deviation (σ) = 84.6 ms.

The empirical rule states that for a normal distribution:

  1. 68% falls within one standard deviation (μ ± σ)
  2. 95% falls within two standard deviation (μ ± 2σ)
  3. 99.7% falls within three standard deviation (μ ± 3σ)

one standard deviation = 394.3 ± 84.6 = (309.7, 478.9). 68% falls within 309.7 and 478.9 ms

two standard deviation = 394.3 ± 2 × 84.6 = (225.1, 563.5). 95% falls within 225.1 and 563.5 ms

three standard deviation = 394.3 ± 3 × 84.6 = (140.5, 648.1). 99.7% falls within 140.5 and 648.1 ms

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Answer:

7/10

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Step-by-step explanation:

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elena55 [62]

Answer:

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Step-by-step explanation:

We can use the determinant, which says that for a quadratic of the form ax² + bx + c, we can determine what kind of solutions it has by looking at the determinant of the form:

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Here, a = 6, b = -20, and c = 1. So, plug these into the determinant formula:

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