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Arisa [49]
4 years ago
8

Graph the following equation y=3(0.5)^X

Mathematics
1 answer:
NemiM [27]4 years ago
4 0

Answer:

He I have no clue what I can get a hold on to it now and again I am going to be a great time with the girls are

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Write an equation in standard form for a line that passes through (2,2) and (0, -3).
Alecsey [184]
First find the slope:
(-3-2)/(0-2)=-5/-2=5/2

So then y=5/2x+b

When x=0, then the y-coordinate with that is the y-intercept.

So the answer is y=5/2x-3.
7 0
4 years ago
Solve the given inequality and graph the solution on a number line. -x/2+3/2<5/2
V125BC [204]

: -x/2+3/2<5/2=x>-2

-x/2+3/2-3/2= -x/2<5/2-3/2=1

-x/2<1

-x/2/2= -x<1/2

-x can be transformed into -1/2x

-1/2x / -1/2=x

1/-1/2=-2

<span>x>-2</span>

5 0
3 years ago
Write a rational inequality with the solution: (-2,-1)U(1, oo)
serg [7]

Answer:

\displaystyle \frac{x^2+3x+2}{1-x}

Step-by-step explanation:

<u>Rational Inequality</u>

We are given the solution of rational inequality:

(-2,-1) U (1,∞)

The first set suggests a limited zone than can be obtained by a quadratic equation of the form:

(x-a)(x-b)

Where a and b are the roots of the equation, which coincide with the endpoints of the interval. Thus, to get the interval, we can use:

(x+2)(x+1)

Operating:

x^2+3x+2

The second set is an open infinite interval, that can be modeled as a third binomial that changes signs in x=1 and is in the denominator, so x=1 is not included.

Thus, one possible inequality is:

\mathbf{\displaystyle \frac{x^2+3x+2}{1-x}

4 0
3 years ago
What is 1+ 12/4+ 8/4
ExtremeBDS [4]
The answer simplified is 6
6 0
3 years ago
Read 2 more answers
From a random sample of 20 bars selected at random from those produced, calculations gave a mean weight of = 52.46 grams and sta
umka21 [38]

Answer:

(52.30 ; 52.62)

Step-by-step explanation:

Given :

Sample size, n = 20

Mean, xbar = 52.46

Standard deviation, s = 0.42

We assume a t - distribution

The 90% confidence interval

The confidence interval relation :

C.I = xbar ± Tcritical * s/√n

To obtain the Tcritical value :

Degree of freedom, df = n - 1 ; 20 - 1 = 19 ; α = (1 - 0.90) /2 = 0.1/2 = 0.05

Using the T-distribution table, Tcritical = 1.729

We now have :

C.I = 52.46 ± (1.729 * 0.42/√20)

C. I = 52.46 ± 0.1624

C.I = (52.30 ; 52.62)

7 0
3 years ago
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