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2 years ago

Graph the following equation y=3(0.5)^X

Mathematics

1 answer:

NemiM [27]2 years ago

4 0

Answer:

He I have no clue what I can get a hold on to it now and again I am going to be a great time with the girls are

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A factory produces 90 packages of mixed nuts in 1 min. A quality control manager selected 10 of these 90 packages at random and

valentina_108 [34]

Answer:

34

explanation:

First of all, put the numbers in order

30, 31, 31, 32, 33, 35, 35, 35, 36, 36

Then, find the middle number.
In this case, there is an even amount of numbers so, we have to pick the 2 middle numbers which is 33 and 35.

Now all you have to do is add these two numbers together then divide by 2 which will give you 34.

or, in simpler questions like this one, you can just say 34 as you know it is between 33 and 35.

In other questions, it might have and odd amount of numbers, for example:

3, 3, 5, 8, 10

so all you would do here is pick the middle number which would be 5. (it has 2 numbers on each side of it)

7 0

2 years ago

Consider a tank used in certain hydrodynamic experiments. After one experiment the tank contains liters of a dye solution with a

Alja [10]

Answer:

t = 460.52 min

Step-by-step explanation:

Here is the complete question

Consider a tank used in certain hydrodynamic experiments. After one experiment the tank contains 200 liters of a dye solution with a concentration of 1 g/liter. To prepare for the next experiment, the tank is to be rinsed with fresh water flowing in at a rate of 2 liters/min, the well-stirred solution flowing out at the same rate.Find the time that will elapse before the concentration of dye in the tank reaches 1% of its original value.

Solution

Let Q(t) represent the amount of dye at any time t. Q' represent the net rate of change of amount of dye in the tank. Q' = inflow - outflow.

inflow = 0 (since the incoming water contains no dye)

outflow = concentration × rate of water inflow

Concentration = Quantity/volume = Q/200

outflow = concentration × rate of water inflow = Q/200 g/liter × 2 liters/min = Q/100 g/min.

So, Q' = inflow - outflow = 0 - Q/100

Q' = -Q/100 This is our differential equation. We solve it as follows

Q'/Q = -1/100

∫Q'/Q = ∫-1/100

㏑Q = -t/100 + c

$Q(t) = e^{(-t/100 + c)} = e^{(-t/100)}e^{c} = Ae^{(-t/100)}\\Q(t) = Ae^{(-t/100)}$

when t = 0, Q = 200 L × 1 g/L = 200 g

$Q(0) = 200 = Ae^{(-0/100)} = Ae^{(0)} = A\\A = 200.\\So, Q(t) = 200e^{(-t/100)}$

We are to find t when Q = 1% of its original value. 1% of 200 g = 0.01 × 200 = 2

$2 = 200e^{(-t/100)}\\\frac{2}{200} = e^{(-t/100)}$

㏑0.01 = -t/100

t = -100㏑0.01

t = 460.52 min

6 0

3 years ago

-43 – 9x = -7 – 3(5x + 6)<br> Answer?

lilavasa [31]

Answer:

Simplifying

9x + 7 = 5x + -3

Reorder the terms:

7 + 9x = 5x + -3

Reorder the terms:

7 + 9x = -3 + 5x

Solving

7 + 9x = -3 + 5x

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '-5x' to each side of the equation.

7 + 9x + -5x = -3 + 5x + -5x

Combine like terms: 9x + -5x = 4x

7 + 4x = -3 + 5x + -5x

Combine like terms: 5x + -5x = 0

7 + 4x = -3 + 0

7 + 4x = -3

Add '-7' to each side of the equation.

7 + -7 + 4x = -3 + -7

Combine like terms: 7 + -7 = 0

0 + 4x = -3 + -7

4x = -3 + -7

Combine like terms: -3 + -7 = -10

4x = -10

Divide each side by '4'.

x = -2.5

Simplifying

x = -2.5

make me brainiest plz!!!

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

For the following rectangular prism, drag and drop the steps needed to find the volume in the correct order. Then type the volum

Kamila [148]

Answer:

Volume = 100 $in^{3}$

Step-by-step explanation:

Volume, V= Bh

length = 10 inches

width = 5 inches

height = 2 inches

So that,

B = 5(10)

= 50 $in^{2}$

B = 50 $in^{2}$

Then,

V = (50)(2)

= 100

v = 100 $in^{3}$

5 0

2 years ago

How do I solve this y=5x +10 (2,14)

AlekseyPX

If you are asking if (2,14) would be a point on the line, it would not because:
14≠5*2+10

Hope this helps :)

3 0

2 years ago