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morpeh [17]
2 years ago
6

A survey was conducted of students at a high school and at a college to determine students favorite subjects the result are show

n in the table
Mathematics
1 answer:
STALIN [3.7K]2 years ago
5 0

I'm suggesting this was supposed to be the table:

A survey was conducted of students at a high school and at a college to determine students' favorite subjects. The results are shown in the table.

History Math Science Total

High School 80 50 70 200

College 70

60

70 200

Total 150 110 140 400

What percentage of the students are college students that prefer history?

O A. 17.5%

OB. 35%

OC. 37.5%

D. 46.7%

E 75%

<h3><u><em>Answer: 35% </em></u></h3>

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Calculate the pH of a buffer solution made by mixing 300 mL of 0.2 M acetic acid, CH3COOH, and 200 mL of 0.3 M of its salt sodiu
Lesechka [4]

Answer:

Approximately 4.75.

Step-by-step explanation:

Remark: this approach make use of the fact that in the original solution, the concentration of  \rm CH_3COOH and \rm CH_3COO^{-} are equal.

{\rm CH_3COOH} \rightleftharpoons {\rm CH_3COO^{-}} + {\rm H^{+}}

Since \rm CH_3COONa is a salt soluble in water. Once in water, it would readily ionize to give \rm CH_3COO^{-} and \rm Na^{+} ions.

Assume that the \rm CH_3COOH and \rm CH_3COO^{-} ions in this solution did not disintegrate at all. The solution would contain:

0.3\; \rm L \times 0.2\; \rm mol \cdot L^{-1} = 0.06\; \rm mol of \rm CH_3COOH, and

0.06\; \rm mol of \rm CH_3COO^{-} from 0.2\; \rm L \times 0.3\; \rm mol \cdot L^{-1} = 0.06\; \rm mol of \rm CH_3COONa.

Accordingly, the concentration of \rm CH_3COOH and \rm CH_3COO^{-} would be:

\begin{aligned} & c({\rm CH_3COOH}) \\ &= \frac{n({\rm CH_3COOH})}{V} \\ &= \frac{0.06\; \rm mol}{0.5\; \rm L} = 0.12\; \rm mol \cdot L^{-1} \end{aligned}.

\begin{aligned} & c({\rm CH_3COO^{-}}) \\ &= \frac{n({\rm CH_3COO^{-}})}{V} \\ &= \frac{0.06\; \rm mol}{0.5\; \rm L} = 0.12\; \rm mol \cdot L^{-1} \end{aligned}.

In other words, in this buffer solution, the initial concentration of the weak acid \rm CH_3COOH is the same as that of its conjugate base, \rm CH_3COO^{-}.

Hence, once in equilibrium, the \rm pH of this buffer solution would be the same as the {\rm pK}_{a} of \rm CH_3COOH.

Calculate the {\rm pK}_{a} of \rm CH_3COOH from its {\rm K}_{a}:

\begin{aligned} & {\rm pH}(\text{solution}) \\ &= {\rm pK}_{a} \\ &= -\log_{10}({\rm K}_{a}) \\ &= -\log_{10} (1.76 \times 10^{-5}) \\ &\approx 4.75\end{aligned}.

7 0
3 years ago
The spherical container has a radius of 21 cm. What is the approximate volume of the container? Use 3. 14 to approximate pi. Rou
Gemiola [76]

Volume of a figure is the measure of the space that figure occupies. The approximate volume of the specified container is 87.92 cm³

<h3>What is the volume of sphere?</h3>

If the given sphere is of radius r units, then its volume is given as:

V=  \dfrac{4}{3} \pi r^3 \: \rm unit^3

For the given case, the radius of the sphere is given to be 21 cm, and the value of pi is instructed to be used  as 3.14

Thus, we have the volume of container as:

V = \dfrac{4}{3} \pi r^3 = \dfrac{4}{3} \times 3.14 \times 21 = 87.92 \: \rm cm^3{

Thus,

The approximate volume of the specified container is 87.92 cm³

Learn more about volume of sphere here:

brainly.com/question/381274

6 0
2 years ago
e is 150% more than d . what is the ratio d:e in its simplest form? what is the ratio e:d in the form 1::n​
Bad White [126]

Answer:

d:e is 2:3

Step-by-step explanation:

if 'e' is 150% more than 'd' we can say that 'e' is 1.5 and 'd' is 1

ratio of 1/1.5 or 1÷3/2 is 2/3

3 0
3 years ago
What is the perimeter of the L-shape?
drek231 [11]

Answer:

There isn't anything i can do when there isn't even a graph or a picture showing what it even looks like so I can't help you maybe re-post it with a picture then i can help.

7 0
2 years ago
What is the volume of a cylinder in a cubic cm,with a height of 8cm and a base diameter of 14 cm?round to the nearest tenth plac
bija089 [108]

Answer:

volume of cylinder = 1232cm³

Step-by-step explanation:

from the question

volume of cylinder =?

height of the cylinder = 8cm

Base diameter of the cylinder = 14cm

to solve this problem we need to know the formula to calculate the volume of a cylinder

volume of cylinder = πr²h

                   or

volume of cylinder = π(d/2)²h........................... if we are given diameter and not radius.

D= 14cm

d = 14/2

d = 7cm

now,

volume of cylinder = π × (7)² × 8

volume of cylinder = 22/7 ×49 ×8

volume of cylinder = 22 × 7 × 8

volume of cylinder = 1232cm³

therefor the volume of the cylinder is equals to 1232cm³

4 0
3 years ago
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