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Radda [10]
2 years ago
7

Eleni is helping to organize a school trip. She needs to find the best deal out of the three bus companies. 260 students are goi

ng on the trip. First Student charges $350 per bus. They will need 7 buses. Stock Transportation charges $500 to cover the cost for the drivers plus $6 per student. Switzer-Carty charges $7 per student. Write an algebraic equation for each company and solve it to find out which is the least expensive.
Mathematics
1 answer:
Tasya [4]2 years ago
7 0

The least expensive is the Stock Transportation charges $500 to cover the cost for the drivers plus $6 per student.

<h3>How to form mathematical expression from the given description?</h3>

You can represent the unknown amounts by the use of variables. Follow whatever the description is and convert it one by one mathematically.

For example, if it is asked to increase some item by 4 , then you can add 4 in that item to increase it by 4.

If something is for example, doubled, then you can multiply that thing by 2 and so on methods can be used to convert description to mathematical expressions.

Let the number of students the bus carries be x.

First Student charges $350 per bus. They will need 7 buses.

Therefore, the cost of the school hiring the bus is:

C = 7*350

C = 2450

The charge of per student

= 2450 / 260

= $ 9.4

Stock Transportation charges $500 to cover the cost for the drivers plus $6 per student.

C = 500 + 6*260

C = 500 + 1560

C = 2060

Switzer-Carty costs $7 for every student that they bus.

Therefore, the cost of the school hiring the bus is:

C = 7 * x

C = 7x

To bus 260 students, then, the cost will be:

C = 7 * 260

C = $1820

Learn more about forming equations here:

brainly.com/question/11938672

#SPJ1

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<h3>What is Demand Function?</h3>

A demand function describes the mathematical relationship between the quantity demanded and one or more determinants of the demand, as the price of the good or service, the price of complementary and substitute goods, disposable income, etc.

Here, given differential equation;

R'(x) = 599 - 0.21\sqrt{x}

we can also write this as;

\frac{d}{dx}R(x) = 599 - 0.21\sqrt{x}

d R(x) = (599 - 0.21\sqrt{x} ) dx

On integrating both sides, we get

\int\ d R(x) = \int\ (599 - 0.21\sqrt{x} ) dx

R(x) = 599x - 0.21 X \frac{2}{3}x^{3/2} + C

R(x) = 599x - 0.14x^{3/2} + C       ...........(i)

Also given, at x = 0, R(x) = 0, Put these values in equation (i), we get

0 = 0 - 0 + C

C = 0

Put the value of C in equation (i), we get

R(x) = 599x - 0.14x^{3/2}

Thus, the integral that is needed to solve the demand function is R(x) = 599x - 0.14x^{3/2}

Learn more about Demand Function from:

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