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Radda [10]
2 years ago
7

Eleni is helping to organize a school trip. She needs to find the best deal out of the three bus companies. 260 students are goi

ng on the trip. First Student charges $350 per bus. They will need 7 buses. Stock Transportation charges $500 to cover the cost for the drivers plus $6 per student. Switzer-Carty charges $7 per student. Write an algebraic equation for each company and solve it to find out which is the least expensive.
Mathematics
1 answer:
Tasya [4]2 years ago
7 0

The least expensive is the Stock Transportation charges $500 to cover the cost for the drivers plus $6 per student.

<h3>How to form mathematical expression from the given description?</h3>

You can represent the unknown amounts by the use of variables. Follow whatever the description is and convert it one by one mathematically.

For example, if it is asked to increase some item by 4 , then you can add 4 in that item to increase it by 4.

If something is for example, doubled, then you can multiply that thing by 2 and so on methods can be used to convert description to mathematical expressions.

Let the number of students the bus carries be x.

First Student charges $350 per bus. They will need 7 buses.

Therefore, the cost of the school hiring the bus is:

C = 7*350

C = 2450

The charge of per student

= 2450 / 260

= $ 9.4

Stock Transportation charges $500 to cover the cost for the drivers plus $6 per student.

C = 500 + 6*260

C = 500 + 1560

C = 2060

Switzer-Carty costs $7 for every student that they bus.

Therefore, the cost of the school hiring the bus is:

C = 7 * x

C = 7x

To bus 260 students, then, the cost will be:

C = 7 * 260

C = $1820

Learn more about forming equations here:

brainly.com/question/11938672

#SPJ1

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The correct works are:

  • Blue(s + h) = 2s^2 + 4sh + 2h^2 + 3.
  • \frac{Blue(s + h) - Blue(s)}{h} = 4s + 2h

<h3>Function Notation</h3>

The function is given as:

Blue(s) = 2s^2 + 3

The interpretation when Steven is asked to calculate Blue(s + h) is that:

Steven is asked to find the output of the function Blue, when the input is s + h

So, we have:

Blue(s + h) = 2(s + h)^2 + 3

Evaluate the exponent

Blue(s + h) = 2(s^2 + 2sh + h^2) + 3

Expand the bracket

Blue(s + h) = 2s^2 + 4sh + 2h^2 + 3

So, the correct work is:

Blue(s + h) = 2s^2 + 4sh + 2h^2 + 3

<h3>Simplifying Difference Quotient</h3>

In (a), we have:

Blue(s + h) = 2s^2 + 4sh + 2h^2 + 3

Blue(s) = 2s^2 + 3

The difference quotient is represented as:

\frac{f(x + h) - f(x)}{h}

So, we have:

\frac{Blue(s + h) - Blue(s)}{h} = \frac{2s^2 + 4sh + 2h^2 + 3 - 2s^2 - 3}{h}

Evaluate the like terms

\frac{Blue(s + h) - Blue(s)}{h} = \frac{4sh + 2h^2}{h}

Evaluate the quotient

\frac{Blue(s + h) - Blue(s)}{h} = 4s + 2h

Hence, the correct work is:

\frac{Blue(s + h) - Blue(s)}{h} = 4s + 2h

Read more about function notations at:

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