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2 years ago

Hello people ~factorise : 5x²+16x+3

Mathematics

2 answers:

atroni [7]2 years ago

7 0

Answer:

Step-by-step explanation:

Remark

If the trinomial is going to factor, it must factor as 5 and 1 paired with 3 and 1 as both 5 and 3 do not factor any further. They are prime numbers.

Let's try this:

(5x + 1) ( 1x + 3)

Both factors must contain an + otherwise something in the given equation would be - when the factors are expanded.

It looks like this works. 5 * 3x + 1x = 16x

son4ous [18]2 years ago

5 0

5x²+16x+3
5x²+15x+x+3
5x(x+3)+1(x+3)
(5x+1)(x+3)

Done!

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4/5 of 60 = 48. 4/5 = .80 Multiply .80 by 60 =48

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3 years ago

Simplify the expression. 5.3x - 9 + 7.6x

babunello [35]

Answer:

12.9x-9

Step-by-step explanation:

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Find the equation of the line perpendicular to y = 3x + 6 and containing the point (-9,-5).

neonofarm [45]

The equation of the line perpendicular to y = 3x + 6 and containing the point (-9,-5) is $y = \frac{-1}{3}x - 8$

Solution:

Given that line perpendicular to y = 3x + 6 and containing the point (-9, -5)

We have to find the equation of line

The slope intercept form is given as:

y = mx + c ------ eqn 1

Where "m" is the slope of line and "c" is the y - intercept

Let us first find the slope of line

The given equation of line is y = 3x + 6

On comparing the given equation of line y = 3x + 6 with eqn 1, we get,

m = 3

Thus the slope of given equation of line is 3

We know that product of slopes of given line and slope of line perpendicular to given line is equal to -1

Slope of given line $\times$ slope of line perpendicular to given line = -1

$3 \times \text{ slope of line perpendicular to given line }= -1$

$\text{ slope of line perpendicular to given line } = \frac{-1}{3}$

Let us now find the equation of line with slope $m = \frac{-1}{3}$ and containing the point (-9, -5)

Substitute $m = \frac{-1}{3}$ and (x, y) = (-9, -5) in eqn 1

$-5 = \frac{-1}{3}(-9) + c\\\\-5 = 3 + c\\\\c = -8$

Thus the required equation of line is:

Substitute $m = \frac{-1}{3}$ and c = -8 in eqn 1

$y = \frac{-1}{3}x - 8$

Thus the required equation of line perpendicular to given line is found

6 0

4 years ago

Hello people ~factorise : 5x²+16x+3​

Hello people ~factorise : 5x²+16x+3