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2 years ago

Hello people ~factorise : 5x²+16x+3

Mathematics

2 answers:

atroni [7]2 years ago

7 0

Answer:

Step-by-step explanation:

Remark

If the trinomial is going to factor, it must factor as 5 and 1 paired with 3 and 1 as both 5 and 3 do not factor any further. They are prime numbers.

Let's try this:

(5x + 1) ( 1x + 3)

Both factors must contain an + otherwise something in the given equation would be - when the factors are expanded.

It looks like this works. 5 * 3x + 1x = 16x

son4ous [18]2 years ago

5 0

5x²+16x+3
5x²+15x+x+3
5x(x+3)+1(x+3)
(5x+1)(x+3)

Done!

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Answer:*******************brainliest

almond37 [142]

Answer:

How is your day going lol

Step-by-step explanation:

was this supposed to be a question lol>

8 0

3 years ago

How do I solve this

sdas [7]

$\bf \textit{difference of squares}
\\ \quad \\
(a-b)(a+b) = a^2-b^2\qquad \qquad 
a^2-b^2 = (a-b)(a+b)\\\\
-------------------------------\\\\
\cfrac{2x}{x^2+2x-24}-\cfrac{x}{x^2-36}\quad 
\begin{cases}
x^2+2x-24\implies (x+6)(x-4)\\
--------------\\
x^2-36\implies x^2-6^2\\
(x-6)(x+6)
\end{cases}$

$\bf \cfrac{2x}{(x+6)(x-4)}-\cfrac{x}{(x-6)(x+6)}\impliedby 
\begin{array}{llll}
\textit{thus our LCD is}\\
(x-6)(x+6)(x-4)
\end{array}
\\\\\\
\cfrac{[(x-6)2x]~-~[(x-4)x]}{(x-6)(x+6)(x-4)}\implies \cfrac{2x^2-12x-x^2+4x}{(x-6)(x+6)(x-4)}
\\\\\\
\cfrac{x^2-8x}{(x-6)(x+6)(x-4)}$

3 0

3 years ago

PLS HELP ME WITH FINDING THE VOLUME OF THIS SOLID

Fofino [41]

Lwh = (3+3+6) (4) (7)

12 x 4 x 7 = 336

3 0

3 years ago

Part À : Find a rational number that is between 9.5 and 9.7 - Explain why is it rational

noname [10]

9514 1404 393

Answer:

A. 9.6

B. √92 ≈ 9.59

Step-by-step explanation:

A. 9.6 is a rational number between 9.5 and 9.7. It is rational because it is a terminating decimal.

B. √92 is an irrational number between 9.5 and 9.7. It is irrational because it is the square root of an integer that is not a perfect square. Its decimal value is about 9.59.

6 0

3 years ago

Create the quadratic function that contains the points (0,2), (1,0), and (3,10). Show all of your work for full credit.

Marina86 [1]

Answer:

y=7/3x²-13/3x+2

Step-by-step explanation:

Determine the value of c:

y=ax²+bx+c

2=a(0)²+b(0)+c

2=c

Substitute (1,0) into the quadratic and create an equation with a and b:

y=ax²+bx+2

0=a(1)²+b(1)+2

0=a+b+2

-2=a+b

Do the same with (3,10) to get a second equation:

y=ax²+bx+2

10=a(3)²+b(3)+2

10=9a+3b+2

8=9a+3b

Set the two equations equal to each other and solve for a and b:

-2=a+b

8=9a+3b

Multiply first equation by 3 and eliminate b to find a:

-6=3a+3b

- (8=9a+3b)

_______

-14=-6a

14/6=a

7/3=a

Substitute 7/3=a into the first equation:

-2=7/3+b

-2-(7/3)=b

-13/3=b

Final equation:

y=7/3x²-13/3x+2

See the graph for a visual representation

7 0

3 years ago

Hello people ~factorise : 5x²+16x+3​

Hello people ~factorise : 5x²+16x+3