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VladimirAG [237]
1 year ago
15

Yes or no easy math plus another math question

Mathematics
1 answer:
Fed [463]1 year ago
3 0

Answer:

10 yes 18 no 17 no

Step-by-step explanation:

Hope this helps

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Mr. Davis has 15 students in his class. He wants to send 3 of his students to pick up books for the class. How many different co
skelet666 [1.2K]
The answer is a.45. 15×3 45
5 0
3 years ago
Find the value of x<br> 12<br> 5<br> X
steposvetlana [31]

Answer:

x = 13

Step-by-step explanation:

Note that the side length x is opposite of the right angle, which means that it is the hypotenuse, which will usually be denoted as c.

Set the equation:

a² + b² = c²

let:

a = 5

b = 12

c = x

Plug in the corresponding numbers (& x) to the corresponding variables:

(5)² + (12)² = (x)²

Simplify. First, solve for the power, and then add:

x² = (5²) + (12²)

x² = (5 * 5) + (12 * 12)

x² = 25 + 144

x² =  169

Next, root both sides of the equation:

√x² = √169

x = √169 = √(13 * 13) = 13

x = 13

~

Note the rules, and it should be easier:

30-60-90° = 1 , √3 , 2

45-45-90° = 1 , 1 , √2

Any other measurements use the equation:  a² + b² = c²

5 0
2 years ago
Amanda's book bag is 0.10. Some of Amanda's pens are removed and replaced with pink pens. Her book bag still contains a total of
Marta_Voda [28]

Answer:

The number of pink pens can be 19 .

Step-by-step explanation:

Total Number of pens = 20

Let x be the number of pink pens

We are supposed to find If the probability of choosing a pink pen is close to 1, how many pink pens would you expect to see in Amanda's bag

Probability of choosing a pink pen = \frac{\text{Number of pink pens}}{\text{Total Number of pens}}

Probability of choosing a pink pen =\frac{x}{20}

ATQ

\frac{x}{20}≈1

x≈20

So, the number of pink pens can be 19 .

6 0
3 years ago
Solve for x 2cos^2x-3cosx+1=0
marishachu [46]
<span> x= Pi, x = 2pi/3, x = 4pi/3
That is the answer</span>
8 0
2 years ago
Solve the following quadratic equation 6x^2-5x-4=0
jeka94

Answer:

=

−

±

2

−

4

√

2

x=\frac{-{\color{#e8710a}{b}} \pm \sqrt{{\color{#e8710a}{b}}^{2}-4{\color{#c92786}{a}}{\color{#129eaf}{c}}}}{2{\color{#c92786}{a}}}

x=2a−b±b2−4ac​​

Once in standard form, identify a, b, and c from the original equation and plug them into the quadratic formula.

6

2

−

5

−

4

=

0

6x^{2}-5x-4=0

6x2−5x−4=0

=

6

a={\color{#c92786}{6}}

a=6

=

−

5

b={\color{#e8710a}{-5}}

b=−5

=

−

4

c={\color{#129eaf}{-4}}

c=−4

=

−

(

−

5

)

±

(

−

5

)

2

−

4

⋅

6

(

−

4

)

√

2

⋅

6

Step-by-step explanation:

6 0
2 years ago
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