344 thousands×<br> 10<br> <br> 1<br> =

An automobile tire manufacturer collected the data in the table relating tire pressure X (in pounds per square inch) andmileage

kaheart [24]

Step 1

Graph the function using the values in the table

Step 2

Find the quadratic function that best fits the data set from the graph

$\begin{gathered} f(x)=-0.517857x^2+33.3929x-484.343 \\ To\text{ 3 d.p, f(x) = -0.}518x^2+33.393x-484.343 \end{gathered}$

Hence,

$\text{f(x) = -0.}518x^2+33.393x-484.343$

4 0

1 year ago

The equation for the motion of an object with constant acceleration is d=vt+0.5at² where d is distance traveled in ft, v is star

sasho [114]

The expression for the distance the car travels after t seconds is d = 200t + 50t²

<h3>Equation of motion </h3>

From the question, we are to write an expression for the distance the car travels after t seconds

From the given information,

The equation for the motion of an object with constant acceleration is

d = vt + 0.5at²

For the race car,

v = 200 ft/s

a = 100 ft/s²

Putting the parameters into the equation, we get

d = 200t + 0.5(100)t²

d = 200t + 0.5 ×100)t²

d = 200t + 50t²

Hence, the expression for the distance the car travels after t seconds is d = 200t + 50t²

Learn more on Equations of motion here: brainly.com/question/20910641

#SPJ1

3 0

2 years ago

100 POINTS QUESTIONS IN PICTURES

stealth61 [152]

First picture
ABC is a triangle so
m<A +m<B+m<C = 180
6x - 1 + 20 + x + 14 = 180
7x + 33 = 180
7x = 180 - 33
7x = 147
x = 147/7
x = 21
m<A = 6x - 1 = 6(21) - 1 = 125
m<C = x + 14 = 21 + 14 = 35
answer:
m<A = 125
m<C = 35
-----------------------------------------
second picture

ABC is a triangle so
m<A +m<B+m<C = 180
48 + 6x - 28 + 2x = 180
8x + 20 = 180
8x = 180 -20
8x = 160
x = 160/8
x = 20

m<B = 6x - 28 = 6(20) - 28 = 120 - 28 = 92
m<C = 2x = 2(20) = 40

answer:
x = 20
m<B = 92
m<C = 40

3 0

3 years ago

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A breeder reactor converts uranium-238 into an isotope of plutonium-239 at a rate proportional to the amount of uranium-238 pres

topjm [15]

Let $U(t)$ denote the amount of uranium-238 in the reactor at time $t$ . As conversion to plutonium-239 occurs, the amount of uranium will decrease, so the conversion rate is negative. Because the rate is proportional to the current amount of uranium, we have

$\dfrac{\mathrm dU}{\mathrm dt}=-kU$

where $k>0$ is constant. Separating variables and integrating both sides gives

$\dfrac{\mathrm dU}U=-k\,\mathrm dt\implies\ln|U|=-kt+C\implies U=Ce^{-kt}$

Suppose we start some amount $u$ . This means that at time $t=0$ we have $U(0)=u$ , so that

$u=Ce^{-0k}\implies C=u\implies U=ue^{-kt}$

We're given that after 10 years, 99.97% of the original amount of uranium remains. This means (if $t$ is taken to be in years) for some starting amount $u$ ,

$0.9997u=ue^{-10k}\implies k=-\dfrac{\ln(0.9997)}{10}$

The half-life is the time $t_{1/2}$ it takes for the starting amount $u$ to decay to half, $0.5u$ :

$0.5u=ue^{-kt_{1/2}}\implies t_{1/2}=-\dfrac{\ln(0.5)}k=\dfrac{10\ln2}{\ln(0.9997)}$

or about 23,101 years. Notice that it doesn't matter what the actual starting amount is, the half-life is independent of that.

7 0

3 years ago

Consider these three squares with known area. 3 squares. The smallest square is labeled 25, the next square is 144, and the larg

Neko [114]

Answer:

The answer is "5, 12, and 13".

Step-by-step explanation:

Please find the complete question in the attached file.

The right triangle is a triangle with only an angle of 90 degrees, as well as the go in the angle of 90 degrees, which is considered a hypotenuse.

The hypotenuse calculation square is equivalent to both the squared measures of the other two sides:

$C^2=A^2+B^2$

And even those squares do verify the equation:

$169 = 144 + 25$

So, it's a rectangular (right) triangle, with sides spanning $5, 12, \ and \ 13.$

3 0

3 years ago

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344 thousands× ​10 ​ ​1 ​​ =

344 thousands× 10 1 =