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Svetlanka [38]
3 years ago
10

I really please need help. Does anyone know these last 6 questions. Brainliest answer and 13 points

Mathematics
1 answer:
Vedmedyk [2.9K]3 years ago
6 0
29. B
30. C
31. 2 cups
32. 1.5 times
33. <span>Because milli means 1/1000 of a meter, centi means 1/100 of a meter while kilo </span><span>means 1000 meters</span>
34. 16 cups =1 gal
16x2= 32
32 cups
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What is the equation of a line that passes through (-5, 0) and (4,18) in slope-intercept form?
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Answer:

Step-by-step explanation:put (-5,0) on top and (4,18) on the bottom subtract the two and you will get the answer

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3 years ago
Simplify this expression. 2 square root 5 (13 + square root 2)
den301095 [7]

Answer:

i'm assuming it's 2*√5(13+√2) so 2√10+26√5

Step-by-step explanation:

5 0
3 years ago
Plsssss help meeeeeee!!
Paladinen [302]

the answer is 6 1/4!

8 0
2 years ago
Two students were asked to find the value of a $1000 item after 3 years. The item was depreciating (losing value) at a rate of 4
Yuki888 [10]

Answer:

<em>Student 2 is incorrect because he didn't use the formula properly</em>

Step-by-step explanation:

The exponential function is often used to model natural growing or decaying processes, where the change is proportional to the actual quantity.

An exponential decaying function is expressed as:

C(t)=C_o\cdot(1-r)^t

Where:

C(t) is the actual value of the function at time t

Co is the initial value of C at t=0

r is the decaying rate, expressed in decimal

The initial value of the item is Co=$1000, the rate of decay is r=40%=0.4, and the time is t=3 years.

Substituting into the formula:

C(3)=\$1000\cdot(1-0.4)^3

C(3)=\$1000\cdot0.6^3

C(3)=$216

Student 2 is incorrect because he didn't use the formula properly

8 0
3 years ago
The Department of Agriculture is monitoring the spread of mice by placing 100 mice at the start of the project. The population,
uranmaximum [27]

Answer:

Step-by-step explanation:

Assuming that the differential equation is

\frac{dP}{dt} = 0.04P\left(1-\frac{P}{500}\right).

We need to solve it and obtain an expression for P(t) in order to complete the exercise.

First of all, this is an example of the logistic equation, which has the general form

\frac{dP}{dt} = kP\left(1-\frac{P}{K}\right).

In order to make the calculation easier we are going to solve the general equation, and later substitute the values of the constants, notice that k=0.04 and K=500 and the initial condition P(0)=100.

Notice that this equation is separable, then

\frac{dP}{P(1-P/K)} = kdt.

Now, intagrating in both sides of the equation

\int\frac{dP}{P(1-P/K)} = \int kdt = kt +C.

In order to calculate the integral in the left hand side we make a partial fraction decomposition:

\frac{1}{P(1-P/K)} = \frac{1}{P} - \frac{1}{K-P}.

So,

\int\frac{dP}{P(1-P/K)} = \ln|P| - \ln|K-P| = \ln\left| \frac{P}{K-P} \right| = -\ln\left| \frac{K-P}{P} \right|.

We have obtained that:

-\ln\left| \frac{K-P}{P}\right| = kt +C

which is equivalent to

\ln\left| \frac{K-P}{P}\right|= -kt -C

Taking exponentials in both hands:

\left| \frac{K-P}{P}\right| = e^{-kt -C}

Hence,

\frac{K-P(t)}{P(t)} = Ae^{-kt}.

The next step is to substitute the given values in the statement of the problem:

\frac{500-P(t)}{P(t)} = Ae^{-0.04t}.

We calculate the value of A using the initial condition P(0)=100, substituting t=0:

\frac{500-100}{100} = A} and A=4.

So,

\frac{500-P(t)}{P(t)} = 4e^{-0.04t}.

Finally, as we want the value of t such that P(t)=200, we substitute this last value into the above equation. Thus,

\frac{500-200}{200} = 4e^{-0.04t}.

This is equivalent to \frac{3}{8} = e^{-0.04t}. Taking logarithms we get \ln\frac{3}{8} = -0.04t. Then,

t = \frac{\ln\frac{3}{8}}{-0.04} \approx 24.520731325.

So, the population of rats will be 200 after 25 months.

6 0
3 years ago
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