Remember the notation..
When you have a triangle called ABD, the angles may be called in theses equivalent ways>
angle A is equivalent to ∠ DAB
angle B is equivalent to ∠ ABD
angle D is equivalen to ∠ BDA
Then given that the two triangles are congruent, you can say an
angle B = angle F = ∠ EFC
So the answer is the last option of the list.
Answer:
Let coordinates of vertex D be (x,y)
In parallelogram diagonals are bisect each other.
∴ Mid-point of AC= Mid-point of BD
⇒ (
2
3+(−6)
,
2
−4+2
)=(
2
−1+x
,
2
−3+y
)
⇒ (
2
−3
,
2
−2
)=(
2
−1+x
,
2
−3+y
)
⇒ (
2
−3
,−1)=(
2
−1+x
,
2
−3+y
)
Now,
⇒
2
−3
=
2
−1+x
⇒ −6=−2+2x
⇒ −4=2x
∴ x=−2
⇒ −1=
2
−3+y
⇒ −2=−3+y
⇒ 1=y
∴ y=1
∴ Coordinates of vertex D is (−2,1)
Let x- intercept represents time
Let y-intercept represents population
Let 1990 represent initial year
Points are (0,14.2)(10,12.4)
slope m= 
= 
General linear equation
y= mx+b --------------(i)
here m is slope and b is intercept
plug the 1st point in equation
14.2= -0.018(0) + b
b=14.2
y= 0.018x + 14.2
replace y with p(t) and x with t
p(t) = -0.018t + 14.2
Well first you do 7+5 to equal 12, and then you multiply 12 by 6 and get 72, then you add the 3 to get 75. 6(7+5)+3=75. Hope this helps!!
