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1 year ago

What is the solution for the equation -15=5(3y-10)-5y

Mathematics

1 answer:

marissa [1.9K]1 year ago

7 0

Answer:

$\Large\boxed{\sf{y=\dfrac{7}{2} }}$

Step-by-step explanation:

Isolate the variable of y from one side of the equation.

-14=5(3y-10)-5y

First, switch sides.

$\sf{5\left(3y-10\right)-5y=-15}$

Use the distributive property.

DISTRIBUTIVE PROPERTY:

A(B-C)=AB-AC

5(3y-10)

Multiply by expand.

5*3y=15y

5*10=50

15y-50-5y

15y-5=10y

= 10y-50

10y-50=-15

Add by 50 from both sides.

10y-50+50=-15+50

Solve.

10y=35

Then, you divide by 10 from both sides.

10y/10=35/10

Solve.

Divide the numbers from left to right.

35/10=7/2

y=7/2

Divide is another option.

7/2=3.5

$\Longrightarrow: \boxed{\sf{y=\dfrac{7}{2}}}$

Therefore, the correct answer is y=7/2.

I hope this helps. Let me know if you have any questions.

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What is the absolute davatation round to the nearest tenth for 6.3, 6.4, 6.5, 6.6, 6.8. 6.8, 7.5?

WITCHER [35]

Let's find the mean of all the values first.
6.3+6.4+6.5+6.6+6.8+6.8+7.5= 46.9
Let's divide by the number of values.
46.9÷7=
6.7
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3 years ago

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Find the midpoint of PQ P(4 1/3, 3 1/6), Q(-2 1/5, 3 2/3)

Paha777 [63]

Answer:

$(1\frac{1}{15},3\frac{5}{12})$

Step-by-step explanation:

To find the midpoint, you must average the x's then average the y's.

So the x's are $4 \frac{1}{3}$ and $-2\frac{1}{5}$ .

The y's are $3\frac{1}{6}$ and $3\frac{2}{3}$ .

To find an average of a data with 2 elements you must add the two elements then take that sum and divide it by 2.

So this is what we will do with the x's then the y's.

So first x:

$\frac{4\frac{1}{3}+-2\frac{1}{5}}{2}$

Write as improper fractions:

$\frac{\frac{13}{3}+\frac{-11}{5}}{2}$

Division by 2 is the same as multiplying by 1/2:

$\frac{13}{6}+\frac{-11}{10}$

The least common multiple of 6 and 10 is 30. We will multiply first fraction by 5/5 and 3/3 for the second so we can have the same denominator.

$\frac{65}{30}+\frac{-33}{30}$

Now that the bottoms are the same we can write as one fraction:

$\frac{65+-33}{30}$

Simplify:

$\frac{32}{30}$

If you want the answer as a mix fraction like your question began as we can do that by first figuring out how many 30's are in 32 and what is the remainder of that division.

There is one 30 and 32 and so 32-30=2 is the remainder.

$1\frac{2}{30}$

Reduce by dividing top and bottom by 2:

$1\frac{1}{15}$

Now for y:

$\frac{3\frac{1}{6}+3\frac{2}{3}}{2}$

Write the mix fractions as improper fractions:

$\frac{\frac{19}{6}+\frac{11}{3}}{2}$

Dividing by 2 is the same as multiplying by 1/2:

$\frac{19}{12}+\frac{11}{6}$

The least common multiple of 12 and 6 is 12 so I'm going to multiply the second fraction by 2/2 so the denominators will be the same:

$\frac{19}{12}+\frac{22}{12}$

Since the denominators are the same we can write as a single fraction:

$\frac{41}{12}$

How many 12's are in 41? 3 and so the remainder is 41-3(12)=41-36=5.

$3\frac{5}{12}$

So the midpoint is:

$(1\frac{1}{15},3\frac{5}{12})$ .

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3 years ago

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If 12,025 was invested at 3.25% compounded monthly 3 years, how much interest will be earned

wariber [46]

Answer:

$1,229.75

Step-by-step explanation:

Lets use the compound interest formula provided to solve this:

$A=P(1+\frac{r}{n} )^{nt}$

P = initial balance

r = interest rate (decimal)

n = number of times compounded annually

t = time

First, change 3.25% into a decimal:

3.25% -> $\frac{3.25}{100}$ -> 0.0325

Since the interest is compounded monthly, we will use 12 for n. Lets plug in the values now:

$A=12,025(1+\frac{0.0325}{12})^{12(3)}$

$A=13,254.75$

Lastly, subtract A from P to get the interest earned:

$13,254.75 - 12,025 = 1,229.75$

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