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<span>1) What is the equation for the line?
</span>slope = 16/2 = 8
answer
equation
y = 8x
<span>2) What is the equation of a line with a slope of 3 and a point (3, 1) on the line?
Express the equation in the form of y=mx+b where m is the slope and b is the y-intercept.
y - 1 = 3(x - 3)
y - 1 = 3x - 9
y = 3x - 8
answer
</span>y = 3x - 8
Answer:
y =3x - 5
Step-by-step explanation:
Well one of the way to do this question is the formula given below your question, but for me, i rather do it this way
OK they gave u y=3x - 12
And they say another line is parallel, once u see the word parallel means they have the same angle, same slope, same gradient ( sorry if I give u the wrong terms, since I learn mine in Malay)
So first u got to understand the slope-intercept form
y = mx + c
y is your y coordinate
x is your x coordinate
m is your gradient ( as in how much the line slants)
c is the y - intercept, as in, if u draw a graph, the y-coordinate where your line touches the y-axis (the vertical line)
So since the say the both lines are parallel, so both of their "m" is the same that is 3. Why? Cuz just compare
y = mx + c
y = 3x - 12
Therefore the m is 3
Therefore u alredy got your first value, so put it in your slope intercept form
y = mx + c
y = 3x + c
Now how to find c? Very easy, just put in the value of y and x from the coordinate ( that the line youre finding is on) they gave u, just put the value in
They gave u
(1, - 2)
So when x = 1, y = - 2
Therefore put it in
y = 3x + c
-2 = 3 (1) + c
c = - 5
Since now u have your m and c value, your slope intercept form is done, just put it in
y = mx + c
y = 3x + (-5)
y = 3x -5
Answer:
2+2=4
Step-by-step explanation:
