Using integration, it is found that the area between the two curves is of 22 square units.
<h3>What is the area between two curves?</h3>
The area between two curves y = f(x) and y = g(x), in the interval from x = a to x = b, is given by:
In this problem, we have that:
.
Hence, the area is:
Applying the Fundamental Theorem of Calculus:
The area between the two curves is of 22 square units.
More can be learned about the use of integration to find the area between the two curves at brainly.com/question/20733870
Answer:
Domain: [-2, 2]
Range: [-3, 3]
Step-by-step explanation:
Domain (x) is the left and right. Range (y) is the up and down.
It's a bracket if it is included, meaning, there is no gap or hole.
If it weren't included, it'd be a parentheses instead "( )". For example, if there was an open circle.
It would go to -infinty or +infinity if it were to go on forever, and that would be in parentheses.
EX: (-∞,∞) or (-∞, 8]
You can mix and match the brackets and parentheses depending on whether or not it touches/includes the number, like I've mentioned.
Answer:
32
Step-by-step explanation:
2(2.5z − 58 + 43) = 176− 46
5z - 116 + 86 = 130
5z -30 = 130
5z = 160
z = 160/5
z = 32
Since this line is parallel to y = 3x + 1 their slopes are equal. The slope is equal to 3. The line is also passing the point (-3,4).
This is the format of the line parallel to y = 3x + 1
y = 3x+ b
This line passes through point (-3, 4)
Replacing the values of y and x coming from the coordinates of (-3, 4)
4 = 3 * (-3) + b
Solving for the y-intercept b
4 = -9 + b
b = 4 + 9
b = 13
Knowing the slope as equal to 3 and the y-intercept as 13 the equation of the line is
y = 3x+13
