Answer: -6 - 5k
Step-by-step explanation:
-3(2+4k) +7(2k-1)
-6+(-12k) + 14k -7k
-6 -12k + 14k - 7k
-6 -5k
The number of passwords that would be allowed if users were allowed to reuse the letters and numbers is 30891577600
<h3>How to determine the number of passwords</h3>
The given parameters are:
Password length = 8
Letters = 6
Numbers = 2
There are 26 letters and 10 digits.
Since the letters and the numbers can be repeated, then the number of passwords is:
Count = 26^6 * 10^2
Evaluate
Count = 30891577600
Hence, the number of passwords that would be allowed if users were allowed to reuse the letters and numbers is 30891577600
Read more about combination at:
brainly.com/question/11732255
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Answer:
C
Step-by-step explanation:
because triangle don't work that way
