Answer: cotθ
<u>Step-by-step explanation:</u>
tanθ * cos²θ * csc²θ
= ![\dfrac{sin\theta}{cos\theta} * \dfrac{cos\theta*cos\theta}{} *\dfrac{1}{sin\theta*sin\theta}](https://tex.z-dn.net/?f=%5Cdfrac%7Bsin%5Ctheta%7D%7Bcos%5Ctheta%7D%20%2A%20%5Cdfrac%7Bcos%5Ctheta%2Acos%5Ctheta%7D%7B%7D%20%2A%5Cdfrac%7B1%7D%7Bsin%5Ctheta%2Asin%5Ctheta%7D)
= ![\dfrac{cos\theta}{sin\theta}](https://tex.z-dn.net/?f=%5Cdfrac%7Bcos%5Ctheta%7D%7Bsin%5Ctheta%7D)
= cotθ
Answer: B
<u>Step-by-step explanation:</u>
The parent graph is y = x²
The new graph y = -x² + 3 should have the following:
- reflection over the x-axis
- vertical shift up 3 units
Answers:
- a. Quadrant II
- b. negative
- c.
![\dfrac{\pi}{6}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cpi%7D%7B6%7D)
- d. C
- e.
![-\dfrac{\sqrt{3}}{3}](https://tex.z-dn.net/?f=-%5Cdfrac%7B%5Csqrt%7B3%7D%7D%7B3%7D)
<u>Explanation:</u>
![\dfrac{17\pi}{6} - \dfrac{12\pi}{6} = \dfrac{5\pi}{6}](https://tex.z-dn.net/?f=%5Cdfrac%7B17%5Cpi%7D%7B6%7D%20-%20%5Cdfrac%7B12%5Cpi%7D%7B6%7D%20%3D%20%5Cdfrac%7B5%5Cpi%7D%7B6%7D)
a) Quadrant 2 is: ![\dfrac{\pi}{2} < \theta < \pi](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cpi%7D%7B2%7D%20%3C%20%5Ctheta%20%3C%20%5Cpi)
b) In Quadrant 2, cos is negative and sin is positive, so tan is negative
c)
= ![\dfrac{\pi}{6}](https://tex.z-dn.net/?f=%5Cdfrac%7B%5Cpi%7D%7B6%7D)
d) the reference line is above the x-axis so it is negative --> ![-tan\dfrac{\pi}{6}](https://tex.z-dn.net/?f=-tan%5Cdfrac%7B%5Cpi%7D%7B6%7D)
e) ![tan(\dfrac{5\pi}{6})=\dfrac{1}{-\sqrt{3}}=-\dfrac{\sqrt{3}}{3}](https://tex.z-dn.net/?f=tan%28%5Cdfrac%7B5%5Cpi%7D%7B6%7D%29%3D%5Cdfrac%7B1%7D%7B-%5Csqrt%7B3%7D%7D%3D-%5Cdfrac%7B%5Csqrt%7B3%7D%7D%7B3%7D)
The answer is: Find the mean of the differences with the other numbers in the set<span>. Add the squared differences and then divide the total by the number of items in </span>data<span> in your </span>set; t<span>ake the square root of this mean of differences to </span>find<span> the standard </span>deviation.
Answer:
x=9
Step-by-step explanation:
Answer: The measure of AC is 32.
Explanation:
It is given that the Points B, D, and F are midpoints of the sides of ΔACE. EC = 38 and DF = 16.
The midpoint theorem states that the if a line segments connecting two midpoints then the line is parallel to the third side and it's length is half of the third side.
Since F and D are midpoints of AE and EC respectively.
So by midpoint theorem length of AC is twice of DF.
![AC=2\times DF](https://tex.z-dn.net/?f=AC%3D2%5Ctimes%20DF)
![AC=2\times 16](https://tex.z-dn.net/?f=AC%3D2%5Ctimes%2016)
![AC=32](https://tex.z-dn.net/?f=AC%3D32)
Therefore, the length of AC is 32.
Answer:
100
Step-by-step explanation:
x = 5 × 20 = 100
.........................