Answer:
Suman 37 km/hr
Narayan 43 km/hr
(extremely sorry if this is wrong!!)
Step-by-step explanation:
We can use the formula distance divided by time is speed.
480/6 = 80.
Their speeds must add up to 80 km/hour
Lets set suman as a variable, lets say s.
Narayan has a speed 6 more than suman so we say 6+s
6+s+s = 80
subtract 6 from both sides
s+s = 74
add like terms
s+s = 2s
2s = 74
divide both sides by 2.
74/2=37
s=37
Suman's speed is 37 km/hr.
Narayan's speed would be 6 more than Suman's so we do 6+37
which makes 43 km/hr
Answer:
495
Step-by-step explanation:
12 Choose 4 = (12!) / 4! 8! = (12 · 11 · 10 · 9) / (4 · 3 · 2) = 495
The sine of any acute angle is equal to the cosine of its complement. The cosine of any acute angle is equal to the sine of its complement. of any acute angle equals its cofunction of the angle's complement.
A
C
B
Since m∠A = 22º is given, we know m∠B = 68º since there are 180º in the triangle. Since the measures of these acute angles of a right triangle add to 90º, we know these acute angles are complementary. ∠A is the complement of ∠B, and ∠B is the complement of ∠A.
If we write, m∠B = 90º - m∠A (or m∠A = 90º - m∠B ), and we substitute into the original observation, we have:
Answer:
3+g=- 134
Step-by-step explanation:
