Answer:
12/13
Step-by-step explanation:
The cosine of an angle in a triangle can be calculated as a relation between the adjacent side and the hypothenuse. So, in this case the adjacent side of θ is 24 and the hypothenuse is 26.
Then:
cos(θ) = 24/26 = 12/13
Take the derivative:
g’(x) = 12x^3 - 24x^2
Set equal to zero and solve:
0 = 12x^3 - 24x^2
0 = 12x^2 (x - 2)
x = 0 or x = 2
Plug back into original
g(0) = 3(0^4) - 8(0^3)
g(0) = 0 - 0
g(0) = 0
g(2) = 3(2^2) - 8(2^3)
g(2) = 3(4) - 8(8)
g(2) = 12 - 64
g(2) = -52
There is an absolute max at (0,0) or when x = 0
Simple...
as far as I can see it looks like you need two names for the angle formed..-->>
the angle would be acute
and
complementary
Meaning both those angles <DHR and <DHM have to be both smaller than 90° but when you add them both they should equal 90°.
Thus, your answer.
Answer:
140 is the answer for y2 because x1 is 80 more than x2 so you would subtract y2 by 80
Step-by-step explanation:
pop goes the weasel is quadratic formula song
