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Leno4ka [110]
3 years ago
8

Guys, please help me with this question I'm having trouble in solving this

Mathematics
1 answer:
navik [9.2K]3 years ago
6 0
C I think okay bye now
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What are the solutions for x when y is equal to 0 in the quadratic function y=x^2-8x
Elena L [17]
I would use the quadratic formula for this:

  x = -b ± √b² - 4ac over 2a
  x = 8 ± √64 - 4(1)(0) over 2(1)
  x = 8 ± √64 over 2
  x = 8 <span>± 8 over 2 [simplify]
  x = 4 </span><span>± 4
     x1 = 4 + 4    x2 = 4 - 4
     x1 = 8          x2 = 0


Thus, the solutions for x would be 0 and 8.</span>
5 0
3 years ago
Ms. Alders has $50 to buy prizes for the treasure box in her classroom. She bought 12 packages of stickers, 8 boxes of pencils,
IceJOKER [234]
The answer is $10

if you add up the total price for each of the items it totals to $40, she has $50 so $50-$40=$10

6 0
2 years ago
Whats the difference of squares
stepan [7]
An example of the difference of squares would be: a^2-b^2 = (a+b)(a-b)
6 0
3 years ago
the temperature dropped 3.5 degrees every hour for 5 hours. how much did the temperatures drop in all?
Vadim26 [7]

3.5 * 5 = 17.5degrees


4 0
3 years ago
Evaluate the integral. (Use C for the constant of integration.) <br> cos(x) (8 + 7 sin^2(x)) dx
UNO [17]

Answer: 8 \sin x +7(\dfrac{\sin^3x}{3})+C

Step-by-step explanation:

Consider \int \cos(x) (8+7 \sin^2(x)) \, dx

Substitute  t= sinx

then dt = cos x dx

\int \cos(x) (8+7 \sin^2(x)) \, dx = \int (8+7t^2)dt\\\\ =8t+7(\dfrac{t^3}{3})+C

[\int x^ndx=\dfrac{x^{n+1}}{n+1}+C]

=8 \sin x +7(\dfrac{\sin^3x}{3})+C

Hence, \int \cos(x) (8+7 \sin^2(x)) \, dx=8 \sin x +7(\dfrac{\sin^3x}{3})+C

5 0
3 years ago
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