Ask question

Ask question

All categories

2 years ago

12

URGENT. The cover of a science textbook has a width of (x-2) and a length of (x^2 -5x+4) inches. Find the area of the cover of t

he science textbook.

1 answer:

umka2103 [35]2 years ago

8 0

I believe it would be x^3 - 7x^2 - 6x -8

You might be interested in

NEED HELP FAST ON THESE 2 questions

Fofino [41]

Answer:

hope it helped u a lot

Step-by-step explanation:

plss give me braniest

7 0

2 years ago

I need to know how to do # 1 & #2 & #3

andrew11 [14]

Zxwebtrnymu8i,oykmutjnrbhegvcwexfvrgebthnyjm7uk8i,l

5 0

3 years ago

MY<br> LAST <br> QUESTION (NEED HELP ASAP) PLEASE!!!!

sdas [7]

Answer:

The answer is A

Step-by-step explanation:

5 0

3 years ago

A football team loses 4 yards on each 3 consecutive plays. Find the total change in yard from where the team started

BigorU [14]

Answer:

The Team started at 1st and 10 but finished at 4th and 22, so they lost 12 yards in 3 plays.

Step-by-step explanation:

6 0

2 years ago

A plane takes off from an airport and flies at a speed of 400km/h on a course of 120° for 2 hours. the plane then changes its co

butalik [34]

Answer:

Distance from the airport = 894.43 km

Step-by-step explanation:

Displacement and Velocity

The velocity of an object assumed as constant in time can be computed as

$\displaystyle \vec{v}=\frac{\vec{x}}{t}$

Where $\vec x$ is the displacement. Both the velocity and displacement are vectors. The displacement can be computed from the above relation as

$\displaystyle \vec{x}=\vec{v}.t$

The plane goes at 400 Km/h on a course of 120° for 2 hours. We can compute the components of the velocity as

$\displaystyle \vec{v_1}=$

$\displaystyle \vec{v_1}=\ km/h$

The displacement of the plane in 2 hours is

$\displaystyle \vec{x_1}=\vec{v_1}.t_1=.(2)$

$\displaystyle \vec{x_1}=km$

Now the plane keeps the same speed but now its course is 210° for 1 hour. The components of the velocity are

$\displaystyle \vec{v_2}=$

$\displaystyle \vec{v_2}=km/h$

The displacement in 1 hour is

$\displaystyle \vec{x_2}=\vec{v_2}.t_2=.(1)$

$\displaystyle \vec{x_2}=km$

The total displacement is the vector sum of both

$\displaystyle \vec{x_t}=\vec{x_1}+\vec{x_2}=+$

$\displaystyle \vec{x_t}=km$

$\displaystyle \vec{x_t}=$

The distance from the airport is the module of the displacement:

$\displaystyle |\vec{x_t}|=\sqrt{(-746.41)^2+492.82^2}$

$\displaystyle |\vec{x_t}|=894.43\ km$

8 0

3 years ago