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2 years ago

8

A flower shop manager uses 1,008 roses to make vases that hold a dozen roses each.How many vases does the flower shop manager ma

ke?

1 answer:

Mice21 [21]2 years ago

7 0

<span>He will need 84 (or 7 dozen) vases to hold 1,008 roses which would be 12 roses per vase.</span>

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A surveyor has poles A, B, and C set to form a right triangle with the right angle at B. If the distance from A to B is 35 meter

tia_tia [17]

A^2+b^2=c^2
35^2+25^2=25^2
So the answer is 25

6 0

2 years ago

A 12-sided solid has faces numbered 1 to 12. The table shows the results of rolling the solid 200 times. Find the experimental

OLga [1]

Answer:

The experimental probability of rolling anumber less than 3 is 3/20

Step-by-step explanation:

16+14=30

30/200

=3/20

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2 years ago

What is the surface area of this right rectangular prism with dimensions of 6 inches by 4 inches by 12 inches A. 324 B.256 C.288

VMariaS [17]

Answer:

C

Step-by-step explanation:

(6 * 4 ) * 2 = 48

( 4 * 12 ) * 2 = 96

( 6 * 12 ) * 2 = 144

48 + 96 + 144 = 288

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1 year ago

You are saving money to buy an electric guitar. You deposit $1000 in an account that earns interest compounded annually. The exp

Katena32 [7]

Let's move like a crab, backwards some.

after 2 years?

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$1000\\
r=rate\to 3\%\to \frac{3}{100}\to &0.03\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &2
\end{cases}
\\\\\\
A=1000\left(1+\frac{0.03}{1}\right)^{1\cdot 2}\implies A=1000(1.03)^2$

after 3 years?

$\bf ~~~~~~ \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$1000\\
r=rate\to 3\%\to \frac{3}{100}\to &0.03\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{annually, thus once}
\end{array}\to &1\\
t=years\to &3
\end{cases}
\\\\\\
A=1000\left(1+\frac{0.03}{1}\right)^{1\cdot 3}\implies A=1000(1.03)^3$

is that enough to pay the $1100?

now, let's write 1000(1+r)² in standard form

1000( 1² + 2r + r²)

1000(1 + 2r + r²)

1000 + 2000r + 1000r²

1000r² + 2000r + 1000 <---- standard form.

8 0

2 years ago

HELPPP PLEASE DUE IN 20 minutes

kupik [55]

Answer:

i think its a trick question

Step-by-step explanation:

theres no way theres a righr answer the 20$ on is always ahead

6 0

2 years ago