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natali 33 [55]
2 years ago
9

Predict what would happen to the strength of the electromagnet in each situation. using a battery with a higher voltage: wrappin

g the wire around the nail only three times: changing the direction of the current by reversing the battery connections: using a plastic stick in place of the iron nail: holding the nail vertically rather than horizontally:
Chemistry
1 answer:
aalyn [17]2 years ago
5 0

The the strength of an electromagnet varies with the quantity and direction of current as well as the number of turns in the coil.

<h3>What as is an electromagnet?</h3>

An electromagnet is a material which operates by the principle of electromagnetism.

Electromagnets possesses both electrical and magnetic properties.

The strength of an electromagnet is affected by the current, the number of turns as well as the material of the electromagnet.

The strength of the given electromagnet will be affected thus:

  • increases when using a battery with a higher voltage
  • decreases when wrapping the wire around the nail only three times
  • is unchanged when changing the direction of the current by reversing the battery connections
  • decreases when using a plastic stick in place of the iron nail
  • is greatest when holding the nail vertically rather than horizontally.

Therefore, the strength of an electromagnet is affected by current and number of turns in the coil.

Learn more about electromagnets at: brainly.com/question/12555869

#SPJ1

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Aluminum has an atomic number of 13
with a mass number of 27
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Proteins are large molecules. They enter a cell through
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The answer is; active transport


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7 0
4 years ago
Given the data calculated in Parts A, B, C, and D, determine the initial rate for a reaction that starts with 0.85 M of reagent
elixir [45]

Answer : The initial rate for a reaction will be 3.8\times 10^{-4}Ms^{-1}

Explanation :

Rate law : It is defined as the expression which expresses the rate of the reaction in terms of molar concentration of the reactants with each term raised to the power their stoichiometric coefficient of that reactant in the balanced chemical equation.

The chemical equation will be:

A+B+C\rightarrow P

Rate law expression for the reaction:

\text{Rate}=k[A]^a[B]^b[C]^c

where,

a = order with respect to A

b = order with respect to B

c = order with respect to C

Expression for rate law for first observation:

6.1\times 10^{-5}=k(0.2)^a(0.2)^b(0.2)^c ....(1)

Expression for rate law for second observation:

1.8\times 10^{-4}=k(0.2)^a(0.2)^b(0.6)^c ....(2)

Expression for rate law for third observation:

2.4\times 10^{-4}=k(0.4)^a(0.2)^b(0.2)^c ....(3)

Expression for rate law for fourth observation:

2.4\times 10^{-4}=k(0.4)^a(0.4)^b(0.2)^c ....(4)

Dividing 1 from 2, we get:

\frac{1.8\times 10^{-4}}{6.1\times 10^{-5}}=\frac{k(0.2)^a(0.2)^b(0.6)^c}{k(0.2)^a(0.2)^b(0.2)^c}\\\\3=3^c\\c=1

Dividing 1 from 3, we get:

\frac{2.4\times 10^{-4}}{6.1\times 10^{-5}}=\frac{k(0.4)^a(0.2)^b(0.2)^c}{k(0.2)^a(0.2)^b(0.2)^c}\\\\4=2^a\\a=2

Dividing 3 from 4, we get:

\frac{2.4\times 10^{-4}}{2.4\times 10^{-4}}=\frac{k(0.4)^a(0.4)^b(0.2)^c}{k(0.4)^a(0.2)^b(0.2)^c}\\\\1=2^b\\b=0

Thus, the rate law becomes:

\text{Rate}=k[A]^2[B]^0[C]^1

Now, calculating the value of 'k' by using any expression.

Putting values in equation 1, we get:

6.1\times 10^{-5}=k(0.2)^2(0.2)^0(0.2)^1

k=7.6\times 10^{-3}M^{-2}s^{-1}

Now we have to calculate the initial rate for a reaction that starts with 0.85 M of reagent A and 0.70 M of reagents B and C.

\text{Rate}=k[A]^2[B]^0[C]^1

\text{Rate}=(7.6\times 10^{-3})\times (0.85)^2(0.70)^0(0.70)^1

\text{Rate}=3.8\times 10^{-3}Ms^{-1}

Therefore, the initial rate for a reaction will be 3.8\times 10^{-3}Ms^{-1}

6 0
3 years ago
A change resulting in one or more new substances being formed is a?
dem82 [27]

Answer:

C. Chemical change

Explanation:

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3 0
3 years ago
How to answer all these questions?
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You have to do it to see the results
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