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zhenek [66]
3 years ago
9

what is the correct conversion factor by which to multiply to convert moles of nitrogen to moles of ammonium nitrate (NH4NO3)

Chemistry
2 answers:
Scilla [17]3 years ago
8 0

Answer:

The conversion factor is 0.5, with which we have to multiply moles of nitrogen to convert it into moles of ammonium nitrate.

Explanation:

As given the molecular formula of ammonium nitrate is NH₄NO₃

There are two nitrogen in each molecule.

thus in each mole of ammonium nitrate there are two moles of nitrogen present in it.

It means if there are two moles of nitrogen the mole of ammonium nitrate will be one

If there is one mole of nitrogen the moles of ammonium nitrate is 0.5.

So if we wish to convert moles of nitrogen to moles of ammonium nitrate we have to multiply the moles of nitrogen with 0.5.

The conversion factor is

\frac{molesofammoniumnitrate}{molesofnitrogen}=0.5

Ostrovityanka [42]3 years ago
6 0

Answer:

0.5

Explanation:

1 mole of ammonium nitrate contains 2 moles of nirogen

1 mole of nitrogen converts to 0.5  moles of ammonium nitrate

the conversation factor is 0.5

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Mass = 2.89 g

Explanation:

Given data:

Mass of NH₄Cl = 8.939 g

Mass of Ca(OH)₂ = 7.48 g

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Solution:

2NH₄Cl   +  Ca(OH)₂     →    CaCl₂ + 2NH₃ + 2H₂O

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Number of moles of Ca(OH)₂ :

Number of moles = mass/molar mass

Number of moles = 7.48 g / 74.1 g/mol

Number of moles = 0.10 mol

Now we will compare the moles of ammonia with both reactant.

                      NH₄Cl          :          NH₃

                          2              :           2

                         0.17          :          0.17

                   Ca(OH)₂         :          NH₃

                        1                :           2

                    0.10              :          2/1×0.10 = 0.2 mol

Less number of moles of ammonia are produced by ammonium chloride it will act as limiting reactant.

Mass of ammonia:

Mass = number of moles × molar mass

Mass = 0.17 mol × 17 g/mol

Mass = 2.89 g

6 0
3 years ago
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