Answer is: the solubility of silver oxalate is <span>a. 1.4 × 10-4 m.
</span>
<span>Chemical reaction
(dissociation) of silver oxalate in water:
Ag</span>₂C₂O₄(s) → 2Ag⁺(aq) + C₂O₄²⁻<span>(aq).
Ksp(Ag</span>₂C₂O₄) = [Ag⁺]²·[C₂O₄²⁻<span>].
[C</span>₂O₄²⁻] = x; solubility of oxalate ion.
[Ag⁺] = 2[C₂O₄²⁻<span>] = 2x
1.0·10</span>⁻¹¹ = (2x)² · x = 4x³.
x = ∛1.0·10⁻¹¹ ÷ 4.
x = 1.4·10⁻⁴ M.
Answer:
V = 0.0007678398L
Explanation:
Given parameters:
Number of moles of gas = 3.43moles
Temperature = 273k
pressure = 100kPa = 100000Pa
Unknown:
Volume of gas = ?
Solution
The gas is at standard temperature and pressure, this implies we can use the ideal gas equation to solve for the unknown.
Mathematically, the law is expressed as:
PV = nRT
The unknown here is the Volume, V. We know the other parameters.
P = pressure on the gas
n = number of moles
R = gas constant=0.082
T = temperature
now, we have to make V the subject of the expression:
V = 
V = 
V = 0.0007678398L
5 degrees Celsius equals 41 degrees Fahrenheit
Answer:
Alcohol ( ethanol ) C2H6O.
Alka Seltzer* ( sodium bicarbonate )
Antifreeze ( ethylene glycol ) ...
Antiperspirant (aluminum chlorohydrate) ...
Aspirin* ( acetylsalicylic acid ) ...
Baking powder ( sodium bicarbonate¶ ) ...
Battery acid ( sulphuric acid ) ...
Bleach, laundry ( sodium hypochlorite )
Explanation: