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Sergeeva-Olga [200]
3 years ago
11

In addition to intermolecular forces affecting liquid properties, they also influence gas properties but to a smaller degree. On

e property that is influenced for a gas is the pressure. Intermolecular forces make the molecules attracted to one another which will affect the pressure that they exert on the container walls. This is one of the reasons why not all real gases act "ideally" and why the ideal gas law is not 100% accurate. Consider that you have one rigid container filled with 1 mole of O2 gas and another rigid container filled with 1 mole of Cl2 gas, both of which have the same volume and temperature. Which gas is expected to have a higher pressure and why?
a. O2, because it has stronger intermolecular forces
b. O2, because it has weaker intermolecular forces
c. Cl2, because it has stronger intermolecular forces
d. Cl2, because it has weaker intermolecular forces
Chemistry
1 answer:
irga5000 [103]3 years ago
4 0

Answer:

b) O2, because it has weaker intermolecular forces

Explanation:

The preassure is produced by the collisions of the gas molecules with the walls of its container.

When the intermolecular forces between the gas molecules increase, those molecules start to "slow down" by effect of the interactions. The collisions decrease in frequency and intensity producing a smaller preassure in the container.

Both O2 and Cl2 are non-polar gases and the only intermolecular forces they have are the London ones. Given that the O2 molecules are smaller than the Cl2, the last ones attract each other with more strengh.

Being all that said, the container with the oxygen is expected to have a higher preassure.

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The breaking and forming of bonds between atoms in substances results in changes in the number of electrons in the substance.

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3 years ago
Consider four different samples: aqueous LiF, molten LiF, aqueous AgF, and molten AgF. Current run through each sample produces
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Answer:

Molten LiF forms solid lithium

Aqueous AgF forms solid silver

Aqueous LiF forms hydrogen gas.

Explanation:

Aqueous solution of LiF has water molecule, there will be competing will be two competing cations for reduction, while Li^{+}(aq) andH^{+}(aq).However the reduction potential of H^{+}(aq) is  more than that of the Li^{+}(aq) . Hence, H^{+}(aq) reduced to hydrogen gas.

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An aqueous form of AgF contains water molecules.there will be competing will be two competing cations for reduction, while Ag^{3+}(aq) andH^{+}(aq).However the reduction potential of Ag^{3+}(aq) is  more than that of the H^{+}(aq) . Hence, Ag^{3+}(aq) reduced to solid silver.

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3 years ago
How many grams of CO2 are produced by the combustion of 289 g of a mixture that is 28.6% CH4 and 71.4% C3H8 by mass?
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Answer:

  • <em><u>433g</u></em>

Explanation:

1. Calculate the mass of each reactant gas in the mixture

<u>a) CH₄</u>

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<u>b) C₃H₈</u>

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2. Calculate the mass of CO₂ produced by each gas in the mixture

<u>a) CH₄</u>

i) Balanced chemical equation:

  • CH₄(g) + 2O₂(g) → CO₂(g) + 2H₂O(g)

ii) Number of moles of CH₄:

  • number of moles = mass in grams / molar mass
  • molar mass of CH₄ = 16.04g/mol
  • number of moles = 82.654g / 16.04 g/mol = 5.153 mol

iii) Number of moles of CO₂

  • From the balanced chemical equation, the mole ratio is 1 mol CH₄ : 1 mol CO₂.
  • Hence, 5.153 mol of CO₂ are produced

iv) Convert the number of moles to mass

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  • mass = 5.153 mol × 44.01g/mol = 226.8 g

<u />

<u>b) C₃H₈</u>

i) Balanced chemical equation:

  • C₃H₈(g) + 5O₂(g) → 3CO₂(g) + 4H₂O(g)

ii) Number of moles of C₃H₈:

  • number of moles = mass in grams / molar mass
  • molar mass of C₃H₈ = 44.1g/mol
  • number of moles = 206.346g / 44.1 g/mol = 4.679 mol

iii) Number of moles of CO₂

  • From the balanced chemical equation, the mole ratio is 1 mol C₃H₈ : 1 mol CO₂.
  • Hence, 4.679 mol of CO₂ are produced

iv) Convert the number of moles to mass

  • mass = number of moles × molar mass
  • molar mass of CO₂ = 44.01g/mol
  • mass = 4.679 mol × 44.01g/mol = 205.9 g

3. Total mass of CO₂

Add the two values found above:

  • 226.8g + 205.9g = 432.7g

Round to 3 significant figures: 433g.

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