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Vesna [10]
2 years ago
15

A network administrator needs to allow employees to upload files to a remote server securely. What port should be allowed throug

h the firewall
Computers and Technology
1 answer:
V125BC [204]2 years ago
6 0

The port that the network administrator should use to allow employees to upload files to a remote server securely is Port 22.

<h3>What is Ports 22 in computer system?</h3>

A port is a virtual place in the operating system of a computer network where connections starts and ends.

Types of ports include:

  • well-known ports,
  • registered ports and
  • private ports.

Ports 22 is a common port number that is associated with secure shell login.

Port 22 was assigned to file transfer protocols(FTP) by the Internet Assigned Numbers Authority.

When employees needs to upload files to a remote server, Ports 22 should be used because it is secure and allows remote administration access to the server.

Learn more about computer ports here?

brainly.com/question/18133590

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Which of the following is an easy steps to take to avoid ESSD well working on your computer?
Monica [59]

C.) Keep your body in contact with the metal area of the computer


Generally, you want to keep contact with something metallic with clear path-to-ground. For instance, painted metal can do the job, but not as efficiently.

There are other ways to go about avoiding ESD, but this is the best option given in your question.

7 0
4 years ago
Create an application containing an array that stores eight integers. The application should call five methods that in turn (1)
Butoxors [25]

Answer:

package b4;

public class ArrayMethodDemo {

public static void main(String[] args) {

 // Create an array to store 8 random integers.

 int[] integernumbers = { 3, 4, 6, 9, 5, 6, 7, 2 };

 // Call the display method to show the elements in the array.

 display(integernumbers);

 // Call the method to display the elements in reverse order.

 displayReverse(integernumbers);

 // Call the method to find the sum of the elements.

 sum(integernumbers);

 // Call the method to display all elements less than a limiting value, say 5.

 lessThan(integernumbers, 5);

 // Call the method to display all elements greater than the average of the array

 // elements.

 higherThan(integernumbers);

}

// Method to display the elements in the array.

// The method receives only a single argument which is the array.

// Loop through the array and at every cycle, print out each element

public static void display(int[] arr) {

 System.out.print("All integers in the array : ");

 for (int i = 0; i < arr.length; i++) {

  System.out.print(arr[i] + " ");

 }

 System.out.println();

}

// Method to display the elements in the array in reverse order

// The method receives only a single parameter which is the array

// Loop through the array starting at the last index

// At every cycle, print out the elements in the array

public static void displayReverse(int[] arr) {

 System.out.print("All integers in the array in reverse : ");

 for (int i = arr.length - 1; i >= 0; i--) {

  System.out.print(arr[i] + " ");

 }

 System.out.println();

}

// Method to print out the sum of the elements in the array.

// The method receives only a single parameter which is the array.

// Declare a variable called sum to hold the sum of the elements

// Initialize sum to zero

// Loop through the array and cumulatively add each element to sum

// Print out the sum at the end of the loop

public static void sum(int[] arr) {

 int sum = 0;

 for (int i = 0; i < arr.length; i++) {

  sum += arr[i];

 }

 System.out.println("The sum of the integers in the array is " + sum);

}

// Method to print all values in the array that are less than a limiting

// argument.

// The method has two parameters - the array and the limiting argument.

// Loop through the array and at every cycle,

// check if the current array element is less than the limiting argument.

// If it is, print it out. Else continue

public static void lessThan(int[] arr, int limitingargument) {

 System.out.print("All values less than the limiting argument (" + limitingargument + ") are: ");

 for (int i = 0; i < arr.length; i++) {

  if (arr[i] < limitingargument) {

   System.out.print(arr[i] + " ");

  }

 }

 System.out.println();

}

// Method to print all values in the array that are higher than the average of

// the array.

// The method has one parameter - the array.

// First, calculate the average of the array elements.

// Loop through the array and at every cycle,

// check if the current array element is greater than the average.

// If it is, print it out. Else continue

public static void higherThan(int[] arr) {

 int sum = 0;

 for (int i = 0; i < arr.length; i++) {

  sum += arr[i];

 }

 double average = sum / arr.length;

 System.out.print("All values higher than the calculate average (" + average + ") is ");

 for (int i = 0; i < arr.length; i++) {

  if (arr[i] > average) {

   System.out.print(arr[i] + " ");

  }

 }

 System.out.println();

}

}

Explanation:

The program has been written in Java.

Please go through the comments in the code for explanation.

The source code has also been attached to this response.

Hope this helps!

Download java
3 0
3 years ago
g write a recursive function that prints out all the even numbers between x and y inclusive if x is odd then the print out will
Reil [10]

Answer:

The function written in python is as follows:

def EvenNumbers(x, y):

    if (y < x):

         return

    if (y % 2 == 0):

         EvenNumbers(x, y - 2)

    else:

         EvenNumbers(x, y - 1)

    if (y % 2 == 0):

         print(y)

Explanation:

x represents the lower limit while y represents the upper limit.

So, the recursion will be repeated as long as x <= y

This defines the function

def EvenNumbers(x, y):

This checks if y < x. If yes, the recursion stops execution and return to the main

<em>     if (y < x): </em>

<em>          return </em>

The following if and else condition checks determines the appropriate range of the recursion.

<em>     if (y % 2 == 0): </em>

<em>          EvenNumbers(x, y - 2) </em>

<em>     else: </em>

<em>          EvenNumbers(x, y - 1) </em>

The above takes care of printing starting at x + 1 if x is odd

This checks and prints the even numbers in the range

<em>     if (y % 2 == 0): </em>

<em>          print(y)</em>

<em />

To call the function from main, make use of

EvenNumbers(x, y)

Where x and y are integers

e.g EvenNumbers(2,10), EvenNumbers(1,17), EvenNumbers(3,21)

<em>See attachment</em>

3 0
3 years ago
Where Can I Get Actual Microsoft AZ-900 Exam Questions?
Pachacha [2.7K]

Answer:

Pls check the site "examtopics"

U fill find ur questions there

8 0
4 years ago
Suppose two computers (A &amp; B) are directly connected through Ethernet cable. A is sending data to B, Sketch the waveform pro
ICE Princess25 [194]

Answer:

Physical / Data link layer

Explanation:

If two computers (A & B) are directly connected through Ethernet cable. A is sending data to B, the data would be transmitted if the network is clear but if the network is not clear, the transmission would wait until the network is clear.

The Open Systems Interconnection model (OSI model) has seven layers each with its own function.

The physical layer is the first layer responsible for data transmission over a physical link. The data packets are converted to signals over a transmission media like ethernet cable.

The data link layer is the second layer in the OSI layer responsible for transmission of data packets between nodes in a network. It also provides a way of detecting errors and correcting this errors produced as a result of data transmission.

4 0
4 years ago
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